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Genrish500 [490]
3 years ago
9

1. Solve the equation using the zero-product property. -x(5x – 4) = 0

Mathematics
1 answer:
Oxana [17]3 years ago
6 0

Answer:

x = 0, 4/5

Step-by-step explanation:

The zero-product property states that if the product of a and b is zero, then either a = 0, b = 0, or both terms equal zero

  • Here our a term is -x and our b term is (5x - 4)
  • Setting each term equal to zero and solving for x we get
  • -x = 0 → x = 0
  • 5x - 4 = 0 → 5x = 4 → x = 4/5

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2. George estimates that each bale of hay in his field weighs 62.5 pounds on
saw5 [17]

Answer:

4 trips

Step-by-step explanation:

there are 892 bales of hay

each one weighs about 62.5 pounds

892 * 62.5 = 55,750

George's truck can only carry 8 tons

1 ton = 2,000 pounds

2,000 * 8 = 16,000 pounds

So,

55,750 / 16,000 = 3.484375

But since you can't make 3.484375 trips in a truck, round it up.

3.484375 rounded up equals 4

George has to take 4 trips

7 0
3 years ago
Read 2 more answers
PLEASE HELP!!!!! What is the value of x in the matrix equation below?
Brums [2.3K]

The given matrix equation is,

1.5\left[\begin{array}{cc}x&6\\8&4\end{array}\right] +y\left[\begin{array}{cc}1&4\\3&2\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right].

Multiplying the matrices with the scalars, the given equation becomes,

\left[\begin{array}{cc}1.5x&9\\12&6\end{array}\right] +\left[\begin{array}{cc}y&4y\\3y&2y\end{array}\right] =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]  \\

Adding the matrices,

\left[\begin{array}{cc}1.5x+y&9+4y\\12+3y&6+2y\end{array}\right]  =\left[\begin{array}{cc}z&z\\6z&2\end{array}\right]  \\

Matrix equality gives,

1.5x+y=z\\ 9+4y=z\\ 12+3y=6z\\ 6+2y=2

Solving the equations together,

y=-2\\ 3y-1.5x=9\\ -1.5x=9+6\\ x=-10

We can see that the equations are not consistent.

There is no solution.

3 0
3 years ago
A rectangular cake has a length of 13 1/2 inches and a width of 9 inches. How many whole, square pieces of cake with side length
aleksandr82 [10.1K]
Let’s find the area of the rectangular cake and the square pieces.
I’m going to turn the fractions into decimals since it’s easier for me.
13.5•9
121.5
Now find the area of the square pieces.
2.25•2.25
5.0625
Now divide the area of the cake by the pieces to find how many can fit.
121.5/5.0625
24
So, 24 square pieces can be cut out of the rectangular cake.
7 0
3 years ago
Rewrite the sum product of the gcf 9+15 and a new sum
ycow [4]
GCF(9; 15) = 3

9 = 3 · 3
15 = 3 · 5

9 + 15 = 3 · 3 + 3 · 5 = 3·(3 + 5)

Used distributive property: a(b + c) = ab + ac
5 0
3 years ago
PART A. Expand the polynomial (x2 − y2)2 + (2xy)2, then simplify it by combining like terms.
sweet-ann [11.9K]
(x2-y1)²+(2xy)1 =
x⁴-2x²y²+y⁴+4x²y² =
x⁴+2x²y²+y⁴=
(x²+y²)²
4 0
4 years ago
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