The asymptotes of the reciprocal function are x = 3 and y = 4. Also, the domain is x < 3 or x > 3 and the range is y < 4 or y > 4
<h3>How to determine the values of a, c, d and k?</h3>
The function is given as:
f(x) = -2[1/0.5(x -3)] + 4
A reciprocal function is generally represented as:
f(x) = a[1/(x -c)] + k
So, we have:
a = -2
c = -3 * 0.5
c = -1.5
k = 4
d = 0
Hence, the values of a, c, d and k are -2, -1.5, 0 and 4
<h3>The asymptotes</h3>
We have:
f(x) = -2[1/0.5(x -3)] + 4
Set the radical to 0
y = 0 + 4
Evaluate
y = 4
Set the denominator to 0
x - 3 = 0
Evaluate
x = 3
Hence, the asymptotes are x = 3 and y = 4
<h3>The graph of the function</h3>
See attachment for the graph of the function f(x) = -2[1/0.5(x -3)] + 4
The table of values is
x y
-4 4.6
-2 4.8
2 8
4 0
From the graph of the function, the domain is x < 3 or x > 3 and the range is y < 4 or y > 4
Read more about functions at:
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Answer: The interest is $453.60.
The total amount includes principal + interest. The principal was 630 and the total amount was 1083.60.
1083.60 - 630 = 453.60.
Step-by-step explanation:
1/x^2 / 3/x^3
1/x^2 * x^3/3=x/3
Answer:
The answer is option A
Step-by-step explanation:
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Using the rules of indices
That's
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Simplify the expression
We have
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Again using the rules of indices
That's
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The final answer is
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Hope this helps you
Easy
the easiest way is to imagine that you have a rectangle with a corner cut off
the area of the figure=area of rectangle-area cut off
area that was cut off was a triangle
area of rectangle=length times width
area of triangle=1/2base times height
so we draw imaginary lines like in attachment
find area of rectangle
legnth=9 inch
width=9 inch
area=9 times 9=81 in^2
triangle
the top part is ?+5=9, so the base of triangle=4
the side is ?+4=9, so the base is 5
area=1/2 times 4 times 5=10 in^2
area=rectangle-triangle
area=81-10=71 in^2
