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o-na [289]
3 years ago
8

Which equation can be used to solve for b? B 5 cm C 10 cm b 30° А

Mathematics
1 answer:
dexar [7]3 years ago
6 0
I believe is C (i think)
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How many cylindrical can of bottles 12 cm high and with 6 cm diameter could be filled from a tank containing 125 liters of deter
Orlov [11]

Answer:

368 cans.

Step-by-step explanation:

Volume of 1 can = π r^2 h.

Here h (height) = 12 and r (radius) = 1/2 * 6 = 3 cm.

So V =  π * 3^2 * 12

= 108π cm^3.

The tank hold 125 liters

=  125,000 cm^3, so:

Number of cans that could be filled = 125000/ 108 π

= 368.4.

4 0
3 years ago
Read 2 more answers
Simplify: (6x + 8) − (x + 4)
Rasek [7]

Answer:

5x+4

Step-by-step explanation:

6x+8-x-4

5x+4

3 0
3 years ago
Read 2 more answers
based on the simulation, what is the probability that at most 2 of the next 10 callers will have to wait more than 8 minutes to
Triss [41]

Using the binomial distribution, supposing that 0.3 of the callers have to wait more than 8 minutes to have their calls answered, it is found that there is a 0.3828 = 38.28% probability that at most 2 of the next 10 callers will have to wait more than 8 minutes to have their calls answered.

For each caller, there are only two possible outcomes, either they have to wait more than 8 minutes to have their calls answered, or they do not. The probability of a caller having to wait more than 8 minutes is independent of any other caller, which means that the binomial distribution is used to solve this question.

Binomial probability distribution

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

C_{n,x} = \frac{n!}{x!(n-x)!}

The parameters are:

  • x is the number of successes.
  • n is the number of trials.
  • p is the probability of a success on a single trial.

In this problem:

  • 10 callers, hence n = 10
  • Suppose that 0.3 of them have to wait more than 8 minutes, hence p = 0.3

The probability that <u>at most 2</u> of the next 10 callers will have to wait more than 8 minutes is:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2)

Then

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

P(X = 0) = C_{10,0}.(0.3)^{0}.(0.7)^{10} = 0.0282

P(X = 1) = C_{10,1}.(0.3)^{1}.(0.7)^{9} = 0.1211

P(X = 2) = C_{10,2}.(0.3)^{2}.(0.7)^{8} = 0.2335

Then:

P(X \leq 2) = P(X = 0) + P(X = 1) + P(X = 2) = 0.0282 + 0.1211 + 0.2335 = 0.3828

0.3828 = 38.28% probability that at most 2 of the next 10 callers will have to wait more than 8 minutes to have their calls answered.

A similar problem is given at brainly.com/question/25537909

3 0
3 years ago
Which expressions are equivalent to 1/5 to the power of 4
OLga [1]
U. Would have to multiply 1/5 x 5
8 0
3 years ago
Find the measure of each arc.
Gemiola [76]

9514 1404 393

Answer:

  • GX = 122°
  • XU = 148°
  • UG = 90°

Step-by-step explanation:

Each arc has the same measure as its central angle. The sum of all of them is 360°.

  angle UOG is marked as a 90° angle, so arc UG is 90°.

  angle GOX is marked as 122°, so arc GX is 122°.

  angle XOU fills out the rest of 360°, so its measure is 360° -90° -122° = 148°. That means are XU is 148°.

The arc measures are ...

  • GX = 122°
  • XU = 148°
  • UG = 90°

7 0
3 years ago
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