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ipn [44]
2 years ago
15

Given segment AC and point B that lies on AC,

Mathematics
1 answer:
ololo11 [35]2 years ago
8 0

The total length of the segment AC is the sum of AB and CB, which gives, CB = 9

<h3>How can the length of CB be found?</h3>

The given parameters are;

  • AC = 17
  • AB = 32 + 3•x
  • CB = 57 + 6•x

Required: <em>CB</em>

Solution:

AC = <em>AB + CB</em> by segment addition property

Therefore;

AC = 17 = 32 + 3•x + 57 + 6•x = 89 + 9•x

17 = 89 + 9•x

x =  \frac{17 - 89}{9}  =  - 8

CB = 57 + 6•x = 57 + 6 × (-8) = 9

Therefore;

  • <u>CB = 9</u>

Learn more about segment addition postulate here: brainly.com/question/1721582

#SPJ1

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Answer:

1. P(S) = 373/580

2. P(S|A) = 53/116

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Step-by-step explanation:

Given

---------------------Sale ----- No Sale-----Total

Aggressive ----265 --------315 ----------580

Passive ----------481 ---------99 -----------580

Total --------------746---------414------------1160

A = aggressive approach,

Pa = passive approach,

S = sale,

N= no sale.

(a) Computing P(S)

This is calculated as the division of customers that participated in sales by total customers

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b.

P(S|A) means that the probability that a sales occur given that the aggressive method was used.

To solve this, we check the cell where Sales and Aggressive intersect

The cell element = 265

Total = 580

P(S|A) = 265/580

P(S|A) = 265/580

P(S|A) = 53/116

c.

P(S|Pa) means that the probability that a sales occur given that the passive method was used.

To solve this, we check the cell where Sales and Passive intersect

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3 years ago
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Write the sum using summation notation, assuming the suggested pattern continues. -10 - 2 + 6 + 14 + ... + 110
Nimfa-mama [501]
This is the sum of the arithmetic sequence:
 10 - 2 + 6 + 14 + ... + 110
where:  a 1 = - 10, d = 8
a n = 110
a n = a 1 + ( n - 1 ) * d
110 = - 10 + ( n - 1 ) * 8
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Answer:
The sum is 800.
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