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Lapatulllka [165]
3 years ago
14

Jesse went out for a 4-course meal were he had a choice of 3 salads, 3 appetizers, 4 entrees, and 5 desserts. How many different

four-course meals are possible?
Mathematics
1 answer:
viktelen [127]3 years ago
8 0

Answer:

180 different four-course meals

Step-by-step explanation:

So you have one out of 3 salads, one out of 3 appetizers, one out of 4 entrees, and one out of 5 deserts. To find the number of meals that are possible, multiply 3 by 3 by 4 by 5

3 * 3 = 9

9 * 4 = 36

36 * 5 = 180

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RideAnS [48]

Answer:

41/45

Step by Step Explanation:

Add: 8/

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+ 1/

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10 · 9

+ 1 · 10/

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= 72/

90

+ 10/

90

= 72 + 10/

90

= 82/

90

= 2 · 41/

2 · 45

= 41/

45

For adding, subtracting, and comparing fractions, it is suitable to adjust both fractions to a common (equal, identical) denominator. The common denominator you can calculate as the least common multiple of both denominators - LCM(10, 9) = 90. In practice, it is enough to find the common denominator (not necessarily the lowest) by multiplying the denominators: 10 × 9 = 90. In the following intermediate step, cancel by a common factor of 2 gives 41/

45

.

In other words - eight tenths plus one ninth = forty-one forty-fifths.

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2 years ago
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1 year ago
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At a high school movie night, the refreshments stand sells popcorn and soft drinks. Of the 100 students who came to the movie, 6
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Independent events. Someone does not have to buy popcorn to buy a drink and someone does not have to buy a drink to buy popcorn.
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