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evablogger [386]
4 years ago
15

Explain how you did it!

Mathematics
1 answer:
Sergio [31]4 years ago
5 0
Ratio s 3:8
other one is x:12

3:8=x:12
3/8=x/12
times both sides by 12
36/8=x
4 and 4/8=x
4.5=x
4 and 1/2=x

J is answer
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Answer:

translate: "Which of the following expressions is equivalent to (5 x 5 x 5 x 5)3?"

57???

Step-by-step explanation:

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Solve y = f(x) for x. Then find the input(s) when the output is 10.
elixir [45]

The inputs are 1 and -1 when the output is 2.

Step-by-step explanation:

The given function is

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Then we set y = f (x)

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 x² = y/10

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The final solution is x =1 and x = -1.

7 0
3 years ago
What is the product of (2x - 5)(2x + 5)2 ?
m_a_m_a [10]
8x^2-50 is your answer hopes this helps
6 0
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What is the approximate area of the circle shown below?
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Step-by-step explanation:

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Write and equation for the shift of the parent graph y=1/x
SashulF [63]
You can think of this equation as \bf f(x)=\cfrac{1}{x}\implies f(x)=(x)^{-1}

and thus apply the transformations to it as such

\bf \qquad \qquad \qquad \qquad \textit{function transformations}
\\ \quad \\\\
% left side templates
\begin{array}{llll}
f(x)=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
y=&{{  A}}({{  B}}x+{{  C}})+{{  D}}
\\ \quad \\
f(x)=&{{  A}}\sqrt{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}}(\mathbb{R})^{{{  B}}x+{{  C}}}+{{  D}}
\\ \quad \\
f(x)=&{{  A}} sin\left({{ B }}x+{{  C}}  \right)+{{  D}}
\end{array}\\\\
--------------------\\\\

\bf \bullet \textit{ stretches or shrinks horizontally by  } {{  A}}\cdot {{  B}}\\\\
\bullet \textit{ flips it upside-down if }{{  A}}\textit{ is negative}
\\\\
\bullet \textit{ horizontal shift by }\frac{{{  C}}}{{{  B}}}\\
\left. \qquad  \right. if\ \frac{{{  C}}}{{{  B}}}\textit{ is negative, to the right}\\\\
\left. \qquad  \right.  if\ \frac{{{  C}}}{{{  B}}}\textit{ is positive, to the left}\\\\

\bf \bullet \textit{ vertical shift by }{{  D}}\\
\left. \qquad  \right. if\ {{  D}}\textit{ is negative, downwards}\\\\
\left. \qquad  \right. if\ {{  D}}\textit{ is positive, upwards}\\\\
\bullet \textit{ period of }\frac{2\pi }{{{  B}}}

1)  D = 2, C = +3

2) D = -12, C = -2

3) C = +6, D = 3

4) C = -7, D = -7
7 0
3 years ago
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