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lidiya [134]
3 years ago
8

HELPPPPPPPP PLSSSSSSSSSSSSSSSSS

Mathematics
2 answers:
MaRussiya [10]3 years ago
7 0

Answer:

3139291489

Step-by-step explanation:

sicko mode

nadezda [96]3 years ago
4 0

Answer:

min =10, max = 39,median = 26, Q1 = 15, Q3 =31.5

Step-by-step explanation:

median is on 9th spot,

The first half has eight values, so the median is the average of the middle two values:Q1 = (15+15)/2 = 15.The second half  also has eight values, so the median is the average of the middle two values: Q3 =(31+32)/2 =31.5

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mrs_skeptik [129]
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A pair of jeans is marked up 20% on the original price. The original price was $50. What is the sale price of the pair of jeans
Anarel [89]

Answer:

20% of $50 is $10. This means that the pair of jeans now cost $60 since it got marked up.

Step-by-step explanation:

6 0
3 years ago
PLEASE HELP ASAP!!! CORRECT ANSWER ONLY PLEASE!!
BARSIC [14]

It be 81.

You have to take half of -18 which is -9, and square that, which is 81.

8 0
3 years ago
PLEASE HELP HURRY!!!!!!!!!
Rzqust [24]

Answer:

PC = 14.42 cm

Step-by-step explanation:

If a tangent and secant are drawn from a point outside a circle, then the product of the lengths of the segments of the secant is equal to the square of the length of the tangent.

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6 0
3 years ago
. Using the Binomial Theorem explicitly, give the 15th term in the expansion of (-2x + 1)^19
timofeeve [1]
Let's rewrite the binomial as:
(1 - 2x)^{19}

\text{Binomial expansion:} (1 + x)^{n} = \sum_{r = 0}^n\left(\begin{array}{ccc}n\\r\end{array}\right) (x)^{r}

Using the binomial expansion, we get:
\text{Binomial expansion: } (1 - 2x)^{19} = \sum_{r = 0}^{19}\left(\begin{array}{ccc}19\\r\end{array}\right) (-2x)^{r}

For the 15th term, we want the term where r is equal to 14, because of the fact that the first term starts when r = 0. Thus, for the 15th term, we need to include the 0th or the first term of the binomial expansion.

Thus, the fifteenth term is:
\text{Binomial expansion (15th term):} \left(\begin{array}{ccc}19\\14\end{array}\right) (-2x)^{14}
3 0
3 years ago
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