Answer:
B
Step-by-step explanation:
Becuase 1 divide 1/2
You make the division sign a multiplication sign
1 time 1/2
get the recipricol of 1/2 wich is 2
1 times 2/1
is 2
Given:
Scale of the map 1 1/4cm : 8 yards
Rectangular Park: width : 2 1/2 cm ; length : 6 1/4 cm
Circular Pond: pi = 3.14 ; diameter 1 1/4 cm
Convert mixed factions into fractions.
Scale 1 1/4 = (4*1+1)/4 = 5/4
Width: 2 1/2 = (2*2+1)/2 = 5/2
Length: 6 1/4 = (4*6+1)/4 = 25/4
Diameter: 1 1/4 = (4*1+1)/4 = 5/4
width / scale * 8 yds = width in yards
5/2 ÷ 5/4 = 5/2 * 4/5 = 20/10 = 2 * 8 yds = 16 yds
length / scale * 8 yds = length in yards
25/4 ÷ 5/4 = 25/4 * 4/5 = 100/20 = 5 * 8 yds = 40 yds
Area of a rectangular park = l * w = 40 yds * 16 yds = 640 yds²
diameter / scale * 8 yds = diameter in yards
5/4 ÷ 5/4 = 5/4 * 4/5 = 20/20 = 1 * 8 yds = 8 yds.
radius = d/2 = 8/2 = 4
Area of a circular pond = πr² = 3.14 * 4² = 3.14 * 16yds² = 50.24 yds²
It is written as 35% or 0.35
Hope this helps!! :)
The answer to the question asked is 5.
The least common multiple of 4 and 6 is 12. In the range 140 to 200, there are
... floor(200/12) - ceiling(140/12) + 1 = 16 - 12 + 1 = 5
integers divisible by 12.
_____
The list of answer choices suggests that the question is intended to be, "how many integers are divisible by 4 or 6?"
The number divisible by 4 is
... floor(200/4) - ceiling(140/4) + 1 = 50 - 35 + 1 = 16
The number divisible by 6 is
... floor(200/6) - ceiling(140/6) + 1 = 33 - 24 + 1 = 10
We know from the above that there are 5 values that are divisible by both 4 and 6, so will be counted twice if we simply add the above numbers. Hence the number of values divisible by 4 or 6 is
... 16 + 10 - 5 = 21 . . . . . corresponds to selection C)
Answer: the equation is
5x^2 -30x - 25
Step-by-step explanation:
A quadratic equation is one in which the highest power of the unknown is 2.
The general form of a quadratic equation is expressed as
ax^2 + bx + c
Where c is a constant and a is the leading coefficient
Assuming we want to write the quadratic equation in x, from the information given, the given roots are 5 and 1 and the leading coefficient is 5. We will just multiply the expression by the leading coefficient.
Therefore, the linear factors of the quadratic will be (x-5) and (x-1)
With the leading coefficient as 5, the equation becomes
5(x-5)(x-1)
= 5(x^2 - x - 5x + 5)
= 5(x^2 - 6x + 5)
= 5x^2 -30x - 25
