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fenix001 [56]
4 years ago
8

What is the range of y=sin^-1(x)?

Mathematics
1 answer:
NeTakaya4 years ago
3 0

Answer: [-π/2, π/2]

Step-by-step explanation: The range of y=sin^-^1x is actually equal to the domain of y=sin x, but it wouldn't be a function, according to the definition of a function. But if you restrict the range, it becomes a one-to-one function.

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zheka24 [161]

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