For
y = (x^2 -4)/((x +2)(x^2 -49))
the numerator factors to (x -2)(x +2), so the factor of (x +2) will cancel with that in the denominator, leaving
y = (x -2)/(x^2 -49)
There are points of discontinuity at the hole, x=-2, and at each of the vertical asymptotes, at x=-7, +7.
The horizontal asymptote is y=0.
Answer: (-6, 5)
<u>Step-by-step explanation:</u>
Use the Midpoint Formula:
Separate the x's and y's and solve them individually:
So, the k-coordinate is (-6, 5)