Answer:
P(X ≤ 3) = 0.9933.
Step-by-step explanation:
We are given that the random variable X has a binomial distribution with the given probability of obtaining a success
Also, given n = 5, p =0.2.
The above situation can be represented through binomial distribution;
where, n = number of samples (trials) taken = 5
r = number of success = less than equal to 3
p = probability of success which in our question is 0.20.
Let X = <u><em>A random variable </em></u>
So, X ~ Binom(n = 5, p = 0.20)
Now, the probability that X is less than and equal to 3 is given by = P(X ≤ 3)
P(X ≤ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)
=
=
= <u>0.9933</u>
