Note that x² + 2x + 3 = x² + x + 3 + x. So your integrand can be written as
<span>(x² + x + 3 + x)/(x² + x + 3) = 1 + x/(x² + x + 3). </span>
<span>Next, complete the square. </span>
<span>x² + x + 3 = x² + x + 1/4 + 11/4 = (x + 1/2)² + (√(11)/2)² </span>
<span>Also, for the x in the numerator </span>
<span>x = x + 1/2 - 1/2. </span>
<span>So </span>
<span>(x² + 2x + 3)/(x² + x + 3) = 1 + (x + 1/2)/[(x + 1/2)² + (√(11)/2)²] - 1/2/[(x + 1/2)² + (√(11)/2)²]. </span>
<span>Integrate term by term to get </span>
<span>∫ (x² + 2x + 3)/(x² + x + 3) dx = x + (1/2) ln(x² + x + 3) - (1/√(11)) arctan(2(x + 1/2)/√(11)) + C </span>
<span>b) Use the fact that ln(x) = 2 ln√(x). Then put u = √(x), du = 1/[2√(x)] dx. </span>
<span>∫ ln(x)/√(x) dx = 4 ∫ ln u du = 4 u ln(u) - u + C = 4√(x) ln√(x) - √(x) + C </span>
<span>= 2 √(x) ln(x) - √(x) + C. </span>
<span>c) There are different approaches to this. One is to multiply and divide by e^x, then use u = e^x. </span>
<span>∫ 1/(e^(-x) + e^x) dx = ∫ e^x/(1 + e^(2x)) dx = ∫ du/(1 + u²) = arctan(u) + C </span>
<span>= arctan(e^x) + C.</span>
I have no clue. What is it?
A. False
Why? Because you cut off the triangle. The measurements are 20 mm and 10 mm.
B. True
Why? Because 20*10 = 200
C. False
Why? Because the base is 6 since 26 - 20 is 6. The height is 4, not 6 because 10 - 6 is 4.
D. True
Why? Because like question C., the base is 6, and the height is 4. 6*4 is 24/2 = 12. If you don't get this, the formula for all triangles is b*h*1/2
E. True
Why? Because from questions B. and D., the area of the rectangle is 200 and the area of the triangle is 12. 200 + 12 = 210.
Hope this helped,
Loafly
<span>3 is to 4 as 12 is to x, or 3/4 = 12/x </span>
Answer:
1/2
Step-by-step explanation: