Answer:
Four-door sedan = 22
Two-door coupes = 6
Step-by-step explanation:
This is an algebra problem.
Let "<em>x</em>" represent number of four-door sedan,
"<em>y</em>" represent two-door coupe.
Since there are total of 28 autos on which film is applied, we have:
<em>x</em> + <em>y</em> = 28 Equation 1
<em>y </em>= 28 - <em>x </em>Equation 2
Also provided,
Total revenue = $3,459.72
That means,
129.99<em>x </em>+ 99.99<em>y</em> = 3,459.72 Equation 3
Putting value of "<em>y</em>" from Equation 2 in Equation 3 we have:
129.99<em>x</em> + 99.99(28 - <em>x</em>) = 3,459.72
129.99x + 2,799.72 - 99.99<em>x</em> = 3,459.72
30<em>x</em> = 660
<em>x </em>= 
Therefore, number of four door sedans = 22
Further <em>y</em> that is two door sedan = 28 - <em>x = </em>28 - 22 = 6
Answer:
Since the triangles are congruent, ∠B = ∠E by CPCTC which means:
2x + 31 = 7x - 24
55 = 5x
x = 11
Answer:
The cost of 10 days at Healthy Gym is $25
Answer:
The speed of the airplane in still air is 550 mph.
The speed of the wind is 50 mph.
Step-by-step explanation:
speed = distance / time
distance = speed * time
or simply
d = st
Let v be the speed of the airplane with no wind.
Let w = speed of wind
With the wind:
d = 1800; s = v + w; t = 3
1800 = 3(v + w)
Against the wind:
d = 1800; s = v - w; t = 3.6
1800 = 3.6(v - w)
We have a system of two equations:
3(v + w) = 1800
3.6(v - w) = 1800
Divide both sides of the first equation by 3. Divide both sides of the second equation by 3.6.
v + w = 600
v - w = 500
Add the equations.
2v = 1100
v = 550
The speed of the airplane in still air is 550 mph.
v + w = 600
550 + w = 600
w = 50
The speed of the wind is 50 mph.
