If the value for three years is $3500 then the answer should be $7000. you would take 3500 and multiply it by 2 because 3 years plus 3 years is 6 years
Answer:
Number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600
Explanation:
Lowest four digit positive integer = 1000
Highest four digit positive integer less than 4000 = 3999
We know that multiples of 5 end with 0 or 5 in their last digit.
So, lowest four digit positive integer which is a multiple of 5 = 1000
Highest four digit positive integer less than 4000 which is a multiple of 5 = 3995.
So, the numbers goes like,
1000, 1005, 1010 .....................................................3990, 3995
These numbers are in arithmetic progression, so we have first term = 1000 and common difference = 5 and nth term(An) = 3995, we need to find n.
An = a + (n-1)d
3995 = 1000 + (n-1)x 5
(n-1) x 5 = 2995
(n-1) = 599
n = 600
So, number of positive four-digit integers which are multiples of 5 and less than 4,000 = 600
That is not enough information.
If you look at the graphic, diagonal BD (along with point E), can be moved up and down the long diagonal and the two diagonals will still have the same length. You need to state additional information.
Answer:
Solution given:
The area of a circle =80.86cm²
we have:
The area of a circle =πr²
substituting value of area of circle we get
80.86cm=3.14*r²
dividing both side by 3.14
80.86/3.14=3.14*r²/3.14
25.75=r²
doing square root on both side

r=5.07cm
<u>The</u><u> </u><u>length</u><u> </u><u>of</u><u> </u><u>radius</u><u> </u><u>is</u><u> </u><u>5</u><u>.</u><u>0</u><u>7</u><u>cm</u>
Probability of finding no defective bulb
=95/100*94/99....86/91
=95!/(85!) / (100!/90!)
= 110983/190120
=>
Probability of finding at least one defective bulb
=1-110983/190120
= 79137/190120
= 0.41625 (to 5 decimal places)