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saveliy_v [14]
3 years ago
12

Henry, Brian and Colin share some sweets in the ratio 6:4:1. Henry gets 25 more sweets than Colin. How many sweets are there alt

ogether?
Mathematics
1 answer:
Dimas [21]3 years ago
7 0

Answer:

There are 55 sweets in total.

Step-by-step explanation:

The total number of sweets is t.

Henry, Brian and Colin share some sweets in the ratio 6:4:1.

This means that Henry earns \frac{6}{6+4+1} = \frac{6}{11} of the total(t).

Brian earns \frac{4}{11} of the total.

Colin earns \frac{1}{11} of the total

Henry gets 25 more sweets than Colin.

Henry earns \frac{6t}{11}

Colin earns \frac{t}{11}

So

\frac{6t}{11} = \frac{t}{11} + 25

Multiplying everything by 1

6t = t + 275

5t = 275

t = \frac{275}{5}

t = 55

There are 55 sweets in total.

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First, let's move y to one side so we can solve for x.
2x-3y=9
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y=(11-5x)/4

Now that they both equal the same thing (y), we can set them equal to each other and solve for x. This will give us the x value for the point of intersection of the lines.
(11-5x)/4=(2x-9)/3
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Now, we can do the opposite, and solve for x to find the y coordinate.
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5 0
4 years ago
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99 and 21 are divisible by 3, so we can divide them both by it:

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but that's all we can do!

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storchak [24]
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7 0
3 years ago
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Solve for xxx.<br> \dfrac{4^{6}}{4^x}=4^0 <br> 4 <br> x<br><br> 4 <br> 6<br><br> ​<br> =4 <br> 0
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Answer:

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Step-by-step explanation:

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