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Gekata [30.6K]
3 years ago
5

Y = −4x + 3 Graphing equations in slope-intercept form

Mathematics
1 answer:
jok3333 [9.3K]3 years ago
4 0
Y=-4x+3 is already in slope intercept form. Graphed it looks like this

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The vertices of Figure ABCD are A(1,1), B(2,3) C(4,3) and D(5,1). If Figure ABCD is reflected over the line y = -1, find the coo
Vlad [161]

Answer:

  • <u><em>(2, - 5)</em></u>

Explanation:

<em>The line y = -1 </em>is horizontal: parallel to the y-axis.

The point<em> B (2,3)</em> is above <em>the line y = - 1 </em>at a distance equal to the y-coordinate of B (y = 3) less - 1:

  • Δy = 3 - ( - 1) = 4

When the <em>point B (2,3) </em>is <em>reflected over the line y = -1</em>, the x-coordinate does not change.  The image will be 4 units down the line y = -1, thus the y-coordinate will be - 1 - 4 = - 5.

Hence,<em> the coordinates of the vertex B'</em> are x = 2, y = - 5: (2, - 5).

7 0
3 years ago
Read 2 more answers
PLEASE ANSWER THIS ASAP
GuDViN [60]
The last one is a function. A rule for functions is that there can only be one x value or coordinate but there can be multiple y values or coordinates.
5 0
4 years ago
Find the sum of the following infinite geometric series, if it exists.
Katena32 [7]
The sum of an infiinte series exists when the ratio is in the interval (-1,1)

Here the ratio is 1/3, then the sum exists.

The formula for this sum is A / (1 -r); where A is the first term and r is the ratio

Then, the sum is [1/3] / [1 -1/3] = [1/3] / [2/3] = 1/2

Answer: 1/2
8 0
3 years ago
Solve for b. -1/6b=3
Archy [21]

Answer:

b = -18

Step-by-step explanation:

Multiply both sides by -6/1 which is the reciprocal of -1/6

(-6/1)*(-1/6)b=3*(-6/1)

b=-18/1 = -18

3 0
3 years ago
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Select the correct answer. Rewrite the expression x^3+10x^2+13x+39/x^2+2x+1 in the form q(x)+r(x)/b(x).
daser333 [38]

1 step: Divide the polynomial x^3+10x^2+13x+39 by the polynomial x^2+2x+1 with remainder:

x^3+10x^2+13x+39=(x^2+2x+1)(x+8)+(-4x+31).

Here x+8 is quotient and -4x+31 is remainder.

2 step: Substitute previous result into the fraction:

\dfrac{x^3+10x^2+13x+39}{x^2+2x+1}=\dfrac{(x^2+2x+1)(x+8)+(-4x+31)}{x^2+2x+1}=\\ \\=\dfrac{(x^2+2x+1)(x+8)}{x^2+2x+1}+\dfrac{-4x+31}{x^2+2x+1}=(x+8)+\dfrac{-4x+31}{x^2+2x+1}.

Answer: correct choice is A.

8 0
3 years ago
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