False
true
false
i could be wrong but i’m 85% certain
Answer:
y=6x-4
(dark blue)
Step-by-step explanation:
x=0 y=-4
y=6x-4
y=6(0)-4
y=-4
The question is asking what v_final is, given that v_initial is at 300 feet. and v_initial is at 0 feet.
We know there will be a constant downward acceleration of 32.15 ft/s^2.
Use the following equation:
v_final^2 = v_initial^2 + 2ah
v_final^2 = (160 ft/s)^2 + 2(-32.15 ft/s^2)(300 ft) = 6310 ft^2/s^2
v_final = (6310 ft^2/s^2)^1/2 = 79.4 ft/s.
Answer:
The correct answer is B 22/25
Step-by-step explanation:
hope this helps u ;)
Answer:
0.961
Step-by-step explanation:
To answer this, find the area under the standard normal curve to the left of 130 pounds:
Using the function normalcdf( on a TI calculator, we get:
normalcdf(-1000, 130, 100, 17) = 0.961
