Answer:
Incomplete question
This is the complete question
A stone falls from the top of a cliff into the ocean.
In the air, it had an average speed of 16 m/s. In the water, it had an average speed of 3 m/s before hitting the seabed. The total distance from the top of the cliff to the seabed is 127 meters, and the stone's entire fall took 12 seconds.
How long did the stone fall in air and how long did it fall in the water?
Step-by-step explanation:
The stone speed in air Sa =16m/s
The stone speed in water Sw=3m/s
Total distance travelled is 127m
Total time taken is 12 sec
Let time in air be ta
Tune in water be tw
Therefore
Total time =ta +tw
12=ta+tw. ,Equation 1
ta=12-tw. ,Equation 2
Also
Speed is given as
Speed = distance /time
Distance =speed × time
So, total distance = distance traveled in air + distance travelled in water
127= Sa×ta + Sw×tw
127=16ta+3tw. , Equation 3
Substitute equation 2 into. 3
127=16(12-tw)+3tw
127=192-16tw+3tw
127-192=-13tw
-65=-13tw
tw=-65/-13
tw=5 seconds
Also from equation 2
ta=12-tw
ta=12-5
ta=7 seconds
The stone spent 7 seconds in air and spent 5 seconds in water before getting to the seabeds
Here, we want to evaluate the expression
We use the order of operations here PEDMAS ( parentheses, exponents (roots and powers) , division, multiplication, addition and subtraction)
We start out with the parentheses, then move on with the terms outside by multiplication
We have this as follows;
40 divided by 8 is equal to 5 so 5 is going to be the zoom size
Answer:
Step-by-step explanation:
you do part a
Equation 1: 4x+y=2
Equation 2: 3x-3y=9
b
Divide equation 2 by 3
x-y=3
add y to both sides
x=3+y
Sbustitute this into equation 1
4(3+y)=2
12+4y+y=2
5y= -10
y= -2
Plug this into equation 1
4x-2=2
x=1
Part c.
Equation 1: 4x+y=2
Equation 2: 3x-3y=9
divide equation 2 by 3
x-y=3
add the two equations
(x-y)+(4x+y)=2+3
5x=5
x=1
Plug this into equation 1
4(1)+y=2
4+y=2
y= -2
For part a just create a table and graph it