I'm not sure what the options are as this appears to be a multiple choice question, but this probability is as follows:
Someone help and make sure the answer is right please and thank you!!!! :)
1 answer:
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Given that Bill
is on the school archery team. the target has a center bull's-eye and
two rings around the bull's-eye.
Given the table below that gives the probabilities of outcomes.
The probability <span>that Bill will get the next arrow in the inner or outer ring is given by
P(inner ring) + P(outer ring) = 0.297 + 0.423 = 0.72</span>
Therefore, <span>the probability that Bill will get the next arrow in the inner or outer ring is 0.72</span>
Given the table below that gives the probabilities of outcomes.
The probability <span>that Bill will get the next arrow in the inner or outer ring is given by
P(inner ring) + P(outer ring) = 0.297 + 0.423 = 0.72</span>
Therefore, <span>the probability that Bill will get the next arrow in the inner or outer ring is 0.72</span>
Let
x-------> the time in minutes
y-------> the temperature in Fahrenheit degrees
we know that
<u>the change in the y-values between two points is equal to</u>
Substitute the y-values of the point A and B in the formula
<u>the change in the x-values between two points is equal to</u>
Substitute the x-values of the point A and B in the formula
therefore
<u>the answer is</u>
The change in the y-value is and the change in the x-value is