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Feliz [49]
3 years ago
10

5 squirrels were found to have an average weight of 8.9 ounces with a sample standard deviation is 0.9. Find the 95% confidence

interval of the true mean weight.
Mathematics
1 answer:
stira [4]3 years ago
7 0

Answer: ( 8.11 , 9.69)

the 95% confidence interval of the true mean weight

= ( 8.11 , 9.69)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 8.9

Standard deviation r = 0.9

Number of samples n = 5

Confidence interval = 95%

z(at 95% confidence) = 1.96

Substituting the values we have;

8.9+/-1.96(0.9/√5)

8.9+/-1.96(0.4025)

8.9+/- 0.79

= ( 8.11 , 9.69)

Therefore at 95% confidence interval (a,b) = ( 8.11 , 9.69)

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Answer:

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Step-by-step explanation:

To find the greatest common factor (GCF), you will need to find the largest value that both of these monomials can be divided by. There are three different parts to these monomials: the number value, variable a, and variable b.

Find the largest number of each element that can be divided by both.

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4 0
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Answer:

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yulyashka [42]

<u>Answer</u>

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Step-by-step explanation:

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