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Feliz [49]
3 years ago
10

5 squirrels were found to have an average weight of 8.9 ounces with a sample standard deviation is 0.9. Find the 95% confidence

interval of the true mean weight.
Mathematics
1 answer:
stira [4]3 years ago
7 0

Answer: ( 8.11 , 9.69)

the 95% confidence interval of the true mean weight

= ( 8.11 , 9.69)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 8.9

Standard deviation r = 0.9

Number of samples n = 5

Confidence interval = 95%

z(at 95% confidence) = 1.96

Substituting the values we have;

8.9+/-1.96(0.9/√5)

8.9+/-1.96(0.4025)

8.9+/- 0.79

= ( 8.11 , 9.69)

Therefore at 95% confidence interval (a,b) = ( 8.11 , 9.69)

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Answer : 49

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Step-by-step explanation:

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Answer:

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Step-by-step explanation:

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4 0
3 years ago
Read 2 more answers
Rational numbers with distribute property
Svetradugi [14.3K]

I'm not sure what this means. If you have choices you should list them.

(1/2)*(1/4 + 1/6) is an example of what should be given. There are two ways to solve this.

1. Use the distributive property.

1/2*1/4 + 1/2* 1/6

1/8 + 1/12 Which can be added using the LCD of 24

3/24 + 2/24 = 5/24

Method 2

Add what is inside the brackets first.

1/2 ( 1/4 + 1/6)

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Now multiply by 1/2

1/2(5/12) = 5*1/(12 * 2) = 5 / 24 Same answer.

4 0
3 years ago
a school has 450 learners.the ratio of boys to the number of girls is 7:8 determine the number of boys and girls in the school​
Tom [10]

Answer:

Boys : 210

girls: 240

Step-by-step explanation:

7+8=15

450/15=30

boys: 30*7= 210

girls: 240

to make sure......

210+240=450

6 0
3 years ago
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