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Feliz [49]
3 years ago
10

5 squirrels were found to have an average weight of 8.9 ounces with a sample standard deviation is 0.9. Find the 95% confidence

interval of the true mean weight.
Mathematics
1 answer:
stira [4]3 years ago
7 0

Answer: ( 8.11 , 9.69)

the 95% confidence interval of the true mean weight

= ( 8.11 , 9.69)

Step-by-step explanation:

Confidence interval can be defined as a range of values so defined that there is a specified probability that the value of a parameter lies within it.

The confidence interval of a statistical data can be written as.

x+/-zr/√n

Given that;

Mean x = 8.9

Standard deviation r = 0.9

Number of samples n = 5

Confidence interval = 95%

z(at 95% confidence) = 1.96

Substituting the values we have;

8.9+/-1.96(0.9/√5)

8.9+/-1.96(0.4025)

8.9+/- 0.79

= ( 8.11 , 9.69)

Therefore at 95% confidence interval (a,b) = ( 8.11 , 9.69)

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Answer: P(odd) = 0.499

Step-by-step explanation:

Given:

Total number of people = 20

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For the jury to have an odd number of women. it must have either of the three.

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The total possible ways of selecting the 6 people jury is;

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Case 2 : 3 women , 3 men

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Case 3 : 5 women, 1 man

N3 = 8C5 × 12C1

N3 = 672

P(Odd) = (N1+N2+N3)/N

P(odd) = (6336+12320+672)/38760

P(odd) = 19328/38760

P(odd) = 0.499

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