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Pachacha [2.7K]

3 years ago

12

Find the value of x then classify the triangle

1 answer:

butalik [34]3 years ago

4 0

3.)

180-90-59=x
X=31

4.)

180-73-79=x
X=28

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Use the shell method to write and evaluate the definite integral that represents the volume of the solid generated by revolving

faust18 [17]

Answer:

$Volume = \frac{384}{7}\pi$

Step-by-step explanation:

Given (Missing Information):

$y = x^\frac{3}{2}$ ; $y = 8$ ; $x=0$

Required

Determine the volume

Using Shell Method:

$V = 2\pi \int\limits^a_b {p(y)h(y)} \, dy$

First solve for a and b.

$y = x^\frac{3}{2}$ and $y = 8$

Substitute 8 for y

$8 = x^\frac{3}{2}$

Take 2/3 root of both sides

$8^\frac{2}{3} = x^{\frac{3}{2}*\frac{2}{3}}$

$8^\frac{2}{3} = x$

$2^{3*\frac{2}{3}} = x$

$2^2 = x$

$4 =x$

$x = 4$

This implies that:

$a = 4$

For $x=0$

This implies that:

$b=0$

So, we have:

$V = 2\pi \int\limits^a_b {p(y)h(y)} \, dy$

$V = 2\pi \int\limits^4_0 {p(y)h(y)} \, dy$

The volume of the solid becomes:

$V = 2\pi \int\limits^4_0 {x(8 - x^{\frac{3}{2}}}) \, dx$

Open bracket

$V = 2\pi \int\limits^4_0 {8x - x.x^{\frac{3}{2}}} \, dx$

$V = 2\pi \int\limits^4_0 {8x - x^{\frac{2+3}{2}}} \, dx$

$V = 2\pi \int\limits^4_0 {8x - x^{\frac{5}{2}}} \, dx$

Integrate

$V = 2\pi * [{\frac{8x^2}{2} - \frac{x^{1+\frac{5}{2}}}{1+\frac{5}{2}}]\vert^4_0$

$V = 2\pi * [{4x^2 - \frac{x^{\frac{2+5}{2}}}{\frac{2+5}{2}}]\vert^4_0$

$V = 2\pi * [{4x^2 - \frac{x^{\frac{7}{2}}}{\frac{7}{2}}]\vert^4_0$

$V = 2\pi * [{4x^2 - \frac{2}{7}x^{\frac{7}{2}}]\vert^4_0$

Substitute 4 and 0 for x

$V = 2\pi * ([{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}] - [{4*0^2 - \frac{2}{7}*0^{\frac{7}{2}}])$

$V = 2\pi * ([{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}] - [0])$

$V = 2\pi * [{4*4^2 - \frac{2}{7}*4^{\frac{7}{2}}]$

$V = 2\pi * [{64 - \frac{2}{7}*2^2^{*\frac{7}{2}}]$

$V = 2\pi * [{64 - \frac{2}{7}*2^7]$

$V = 2\pi * [{64 - \frac{2}{7}*128]$

$V = 2\pi * [{64 - \frac{2*128}{7}]$

$V = 2\pi * [{64 - \frac{256}{7}]$

Take LCM

$V = 2\pi * [\frac{64*7-256}{7}]$

$V = 2\pi * [\frac{448-256}{7}]$

$V = 2\pi * [\frac{192}{7}]$

$V = [\frac{2\pi * 192}{7}]$

$V = \frac{\pi * 384}{7}$

$V = \frac{384}{7}\pi$

Hence, the required volume is:

$Volume = \frac{384}{7}\pi$

3 0

3 years ago

Keith is riding an ferris wheel.His car turned 120 degrees and stopped .Then his car turn 100 degrees and stop again how many de

vesna_86 [32]

Answer:

220 degrees

Step-by-step explanation:

120 degrees + 100 degrees= 220 degrees

5 0

3 years ago

Select all that apply.

sergejj [24]

Answer:

All of them, I believe.

7 0

3 years ago

Read 2 more answers

How much extra snow would a child need to take a snowball with a diameter of 8 cm and increase its size to a snowball with a dia

Sergio039 [100]

The amount of the extra snow would a child need to take a snowball will be 636.71 cubic cm.

<h3>What is the volume of the sphere?</h3>

Let d be the diameter of the sphere.

Then the volume of the sphere will be

V = 1/6 πd³ cubic units

Then the amount of the extra snow would a child need to take a snowball with a diameter of 8 cm and increase its size to a snowball with a diameter of 12 cm will be

Amount of snow = 1/6 π x 12³ - 1/6 π x 8³

Amount of snow = 288 π - 85.33π

Amount of snow = 636.71 cubic cm

More about the volume of the sphere link is given below.

brainly.com/question/9994313

#SPJ1

4 0

2 years ago

Solve for r. Show your work!<br> 12 =R– (34 – 2)<br><br> Helpppp!!

amm1812

Answer:

r = 44

Step-by-step explanation:

12 = r - (34 - 2)

Solve for r

___________

To solve, we need to isolate r.

Distribute the negative sign with the numbers within the parenthesis :

12 = r - 34 + 2

Add like terms :

12 = r - 32

Add 32 to both sides :

44 = r

r = 44

4 0

3 years ago

Read 2 more answers