A.The genotype frequencies can be determined by dividing the number of individuals with a genotype by the total number all the individuals.
FF genotype frequency:
98÷200=0,49. There are approximately 5 <span>homozygous dominant mice in 10.
Ff genotype frequency:
84</span>÷200=0,42. There are approximately 4 <span>heterozygous mice in 10.
ff genotype frequency:
18</span>÷200=0,09. There are approximately 1 <span>homozygous recessive mouse in 10.
B.To determine the frequency of an allele we can divide the number of times that the allele appears by the total number of alleles.
F allele frequency:
</span>

<span>=0.7
There are 7 F alleles in 10 random alleles.
f </span>allele frequency:

=0.3
There are 3 f alleles in 10 random alleles.<span>
</span>
Answer:
100% red kernel color
Explanation:
R_B_ = Red kernel color
R_bb and rrB_ = yellow kernel color
rrbb = white kernel color
True breeding red kernel x true breeding white kernel = RRBB x rrbb
F1 genotype ratio = 100% RrBb
F1 phenotype ratio = 100% red kernel color plant.
<em>The expected phenotype of the F1 plant is 100% red kernel color.</em>
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<span>several types of : Bacteria are used to produceed yogurt
There are some type of Bacterias that are actually good for out digestive system. In order to make yogurt, the most common type of bacteria that being used are Lactobacillus delbrueckii subsp. bulgaricus and Streptococcus thermophilus bacteria</span>