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77julia77 [94]
3 years ago
9

Which of the following represents 0.63 as a fraction in simplest form?

Mathematics
1 answer:
tino4ka555 [31]3 years ago
5 0

Answer:

63/100

Step-by-step explanation:

0.63 = 63/100

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What is 3.45 written as a percentage?
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345%

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Find the dimensions of an open rectangular glass tank of volume 4 cubic feet for which the amount of material needed to construc
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.. dm/dx = 2x -16/x^2 = 0
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The tank is 2 feet square and 1 ft high.

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You will note that it is half the height of a cube that has double the volume. This is the generic solution to all minimum cost open-top box problems. Actually, the costs of pairs of opposite sides are equal to each other and to the cost of the base. If material costs are not identical in all directions, that is the more generic solution.
8 0
4 years ago
Y for a daily lottery, a person selects a three-digit number. if the person plays for $1, she can win $500. find the expectation
Elena-2011 [213]
The expected value of the first game is -$0.50 and of the second game is -$0.52.

There are 10³ possible numbers for the lottery, and only 1 of them will match in the correct order; this gives a probability of 1/1000.  To find the expected value, we multiply this by the winnings (499 after the $1 cost); we also multiply the probability of losing (999/1000) by the amount lost (-1):
1/1000(499)+999/1000(-1)
499/1000 - 999/1000 = -500/1000 = -0.50

For the second game, since the number is "boxed", there are 3! ways to get the correct digits; this gives a probability of 6/1000.  Multiply this by the winnings, 79 (after the $1 cost); multiply the probability of losing (994/1000) by the loss (-1):
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4 0
3 years ago
) A jar contains 4 white balls and 6 black balls. A ball is chosen at random, and its color noted. The ball is then replaced, al
taurus [48]

Answer:

The answer is "\bold{\frac{2}{5}\ \ and \ \ \frac{6}{13}}".

Step-by-step explanation:

You have 4/10 opportunities to choose a white ball, and there'll be 7 white balls and 6 black balls out of 13, and so the second time they choose a white one is 7/13, as well as the second time they choose a black, 6/13. people will also have a 4/10 chance.  

There are 6/10 chances which users pick its black ball and 4 white balls would still be picked, but 9 black balls and out 13 balls and thus, its second and third time you select the white one is 4/13 but you are likely to pick a black for the second time is 9/13.  

Taking the diagram of the next tree. The very first draw is marked with a and the second draw is marked with b.

\to P(a) = \frac{4}{10}\ \ \ \ \ \ \ \ \ P(b) = \frac{6}{10}\\\\\to P(\frac{a2}{a1}) = \frac{7}{13} \ \ \ \ \ \ \ \ \ \ P(\frac{a}{b}) = \frac{4}{13}\\\\\to P(\frac{b2}{a1}) = \frac{6}{13} \ \ \ \ \ \ \ \ \ \ P(\frac{b2}{b1}) = \frac{9}{13}

Calculating the second drawn ball is white:

\to P(b2)=P(a)P(\frac{a2}{b1})+P(b)P(\frac{a}{b})\\

              =\frac{4}{10}\frac{7}{13}+\frac{6}{10}\frac{4}{13}\\\\=\frac{28}{130}+\frac{24}{130}\\\\=\frac{28+24}{130}\\\\=\frac{52}{130}\\\\=\frac{2}{5}\\\\

In point b:

\to P(\frac{b}{a1})= \frac{P(B)P(\frac{a}{b})}{P(a)P(\frac{a2}{b1})+P(b)P(\frac{a}{b})\\}

              =\frac{\frac{6}{10} \frac{4}{13}}{\frac{52}{130}}\\\\=\frac{\frac{24}{130}}{\frac{52}{130}}\\\\=\frac{24}{130} \times \frac{130}{52}\\\\=\frac{24}{52}\\\\=\frac{6}{13}\\

5 0
4 years ago
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