Question

The line L passes through the points (5, -5) and (1, 2). Find the gradient of line L.

Answer 1

gradient of L = -7/4

Explanation:

$\sf gradient = \dfrac{y_2-y_1}{x_2-x_1}$

Insert the following values.

$\rightarrow \sf \dfrac{2-(-5)}{1-5}$

$\rightarrow \sf \dfrac{7}{-4}$

$\rightarrow \sf -\dfrac{7}{4}$

Answer 2

hello!

Use the slope formula:-

(the slope is the same as the gradient)

$\sf{\displaystyle\frac{y2-y1}{x2-x1} }$

$\sf{\displaystyle\frac{2-(-5)}{1-5}}$

$\sf{\displaystyle\frac{2+5}{-4} }=\frac{7}{-4} ={\boxed{-\frac{7}{4} }}\leftarrow\sf{slope~of~line~L}}}$

note:-

Hope everything is clear; if you need any clarification/explanation, kindly let me know, and I will comment and/or edit my answer :)