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ANTONII [103]
3 years ago
14

Find the interquartile range (IQR) of the data in the box plot below. Asap ASAP Please PLZ

Mathematics
1 answer:
valina [46]3 years ago
8 0

Answer:

3

Step-by-step explanation:

IQR is the difference between the upper and lower medians so the IQR = 7 - 4 = 3

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Can you help me? Please
Anni [7]

9514 1404 393

Answer:

  a.

Step-by-step explanation:

For an even-index radical, ...

  \sqrt[n]{x^n}=|x|\qquad\text{n even}

This lets us simplify the given expression as follows:

  \sqrt[4]{81x^6y^4}-|y|\sqrt[4]{x^6}-\sqrt[4]{16x^2}=\sqrt[4]{(3xy)^4x^2}-|y|\sqrt[4]{x^4x^2}-\sqrt[4]{2^4x^2}\\\\=3|xy|\sqrt[4]{x^2}-|xy|\sqrt[4]{x^2}-2\sqrt[4]{x^2}=\boxed{2|xy|\sqrt[4]{x^2}-2\sqrt[4]{x^2}}

4 0
2 years ago
Write the first four terms of the sequence:<br> a = 2<br> an = a(n-1) + 4
eduard

We have sequence equation a_n=a(n-1)+4.

In this case n is a natural number (1, 2, 3, ...).

So start inserting and computing value of a_n given that you know the value of n and a.

a_1=2(1-1)+4=4 (first term)

a_2=2(2-1)+4=6 \\a_3=2(3-1)+4=8 \\a_4=2(4-1)+4=10

Hope this helps.

3 0
2 years ago
What is the smallest solution to the equation 2/3 x^2=24
True [87]

Answer:

The smallest solution is -6

Step-by-step explanation:

2/3 x^2=24

Multiply by 3/2 on each side

3/2 *2/3 x^2=24 *3/2

x^2 = 36

Take the square root of each side

sqrt(x^2) = ±sqrt(36)

x = ±6

x = -6, 6

The smallest solution is -6

7 0
3 years ago
Log2(3x-1) = log2 (x+8)
Keith_Richards [23]

Answer:

X= 9/2  

Alternative form

x=4 1/2, x=4.5

Step-by-step explanation:

*= Multiply

1. log (little 10 under) (2)*(3x-1)= log (little 10 under) (2)*(x+8)

2. then divide both side by log (little 10 under (2))

3. 3x-1=x+8

4. move variable to the left side and change its sign

5. 3x-x-1=8

6. then move constant to the right side and change its sign

7. 3x-x=8+1

8. collect like terms

9. 2x=8+1

10. add 8+1

11. 2x=9

12. then divide both sides by 2

13. 2/2 9/2

14. 2/2 cancels out so x=9/2 is the answer

4 0
3 years ago
Read 2 more answers
Solve for x:<br> (2x/3) + 10 = (x/5) + (36/5)
Reil [10]

Answer:

x = -6

Step-by-step explanation:

(2x/3) + 10 = (x/5) + (36/5)

15*[(2x/3) + 10 = (x/5) + (36/5)]   <em>[Multiply both sides by 15 in order to convert the fractions to whole numbers]</em>

(15/3)*2x +15*10 = (15/5)x + (15/5)*36

5*2x + 150 = 3x + 3*36

10x +150 = 3x + 108

7x = -42

x = -6

===

<u>Check:</u>

Does (2x/3) + 10 = (x/5) + (36/5) work for x = -6?

(2(-6)/3) + 10 = (-6/5) + (36/5) ?

-4 + 10 = (30/5) ?

6 = 6  YES

4 0
2 years ago
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