Answer:
35, 15
Step-by-step explanation:
Let the present age of the younger person = x
Then the present age of the older person = 50 - x
After (50 - x) - x years, the younger person will be x + [(50 - x) - x} = 50 - x, the older person will be 50 - x + (50 - x) - x = 100 - 3x
Theire age sum will be (50 - x) + (100 - 3x) = 90
150 - 4x = 90
4x = 150 - 90 = 60
x = 60/4 = 15
50 - x = 35
Answer:
<u>Answer (a):</u>
s + l = 22 ... (i)
43s + 75l = 1234 ... (ii)
<u>Answer (b)</u>
9 large dogs.
Step-by-step explanation:
Paws at Play made a total of $1234 grooming 22 dogs.
Paws at Play charges $43 to groom each small dog and;
$75 for each large dog.
Let the number of small dogs be 's'
And the number of large dogs be 'l'
<u>A system of equations will be:</u>
s + l = 22 ... (i)
43s + 75l = 1234 ... (ii)
Solving this set of simultaneous equations by elimination, we simply multiply (i) by 43 to get;
43s + 43l = 946 ... (i)
43s + 75l = 1234 ... (ii)
Subtracting (i) from (ii) we get;
32l = 288 , l = 
= 9
So there are 9 large dogs.
Problem 1)
The base of the exponential is 12 which is also the base of the log as well. The only answer choice that has this is choice B.
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Problem 2)
log(x) + log(y) - 2log(z)
log(x) + log(y) - log(z^2)
log(x*y) - log(z^2)
log[(x*y)/(z^2)]
Answer is choice D
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Problem 3)
log[21/(x^2)]
log(21) - log(x^2)
log(21) - 2*log(x)
This matches with choice B
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Problem 4)
Ln(63) = Ln(z) + Ln(7)
Ln(63)-Ln(7) = Ln(z)
Ln(63/7) = Ln(z)
Ln(9) = Ln(z)
z = 9
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Problem 5)
Ln(5x-3) = 2
5x-3 = e^2
5x = e^2+3
x = (e^2+3)/5
This means choice A is the answer
Answer:
x=2
Step-by-step explanation:
0.95x +0.05(12-x) = 0.10(24)
Distribute
0.95x +0.6-0.5x= 2.4
add/subtract like terms
0.9x+0.6=2.4
subtract 0.6 from both sides
0.9x=1.8
Divide both sides by 9
0.1x=0.2
multiply both sides by 10
x=2
Hope this helps! Plz award Brainliest : )
