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Kisachek [45]
3 years ago
14

1/2 divided by 3/4 in simplest form

Mathematics
2 answers:
katrin [286]3 years ago
4 0

Answer:

4/11

Step-by-step explanation:

enot [183]3 years ago
3 0

Answer:

3/2 or 1 1/2

Step-by-step explanation:

.

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Quadrilateral ABCD is to be reflected across a horizontal line that is 3 units below point C.
brilliants [131]
D. because from b to the horizontal line is 5 units, and to reflect it across the horizontal axis, you would add another 5 units, so you would get a total of 10 units. <span />
4 0
3 years ago
Read 2 more answers
What is one of the solutions to the following systems of equations? Y squared plus X squared equals 65 and Y plus X equals seven
alukav5142 [94]

Answer:

Step-by-step explanation:

y^2 + x^2 = 65

y + x = 7......x = 7 - y

y^2 + (7 - y)^2 = 65

y^2 + (7 - y)(7 - y) = 65

y^2 + 49 - 7y - 7y + y^2 = 65

2y^2 - 14y + 49 = 65

2y^2 - 14y + 49 - 65 = 0

2y^2 - 14y - 16 = 0

2(y^2 - 7y - 8) = 0

2(y + 1)(y - 8) = 0

y + 1 = 0        y - 8 = 0

y = -1             y = 8

solution :

y = -1...........y + x = 7.....-1 + x = 7......x = 7 + 1......x = 8........(8,-1)

y = 8........y + x = 7.....8 + x = 7......x = 7 - 8........x = -1........(-1,8)

7 0
3 years ago
2.The number of grams A of a certain radioactive substance present at time, in yearsfrom the present, t is given by the formulaA
professor190 [17]

Answer:

Given that,

The number of grams A of a certain radioactive substance present at time, in years

from the present, t is given by the formula

A=45e^{-0.0045(t)}

a) To find the initial amount of this substance

At t=0, we get

A=45e^{-0.0045(0)}A=45e^0

We know that e^0=1 ( anything to the power zero is 1)

we get,

A=45

The initial amount of the substance is 45 grams

b)To find thehalf-life of this substance

To find t when the substance becames half the amount.

A=45/2

Substitute this we get,

\frac{45}{2}=45e^{-0.0045(t)}

\frac{1}{2}=e^{-0.0045(t)}

Taking natural logarithm on both sides we get,

\ln (\frac{1}{2})=-0.0045(t)^{}(-1)\ln (\frac{1}{2})=0.0045(t)\ln (\frac{1}{2})^{-1}=0.0045(t)\ln (2)=0.0045(t)0.6931=0.0045(t)t=\frac{0.6931}{0.0045}t=154.02

Half-life of this substance is 154.02

c) To find the amount of substance will be present around in 2500 years

Put t=2500

we get,

A=45e^{-0.0045(2500)}A=45e^{-11.25}A=45\times0.000013=0.000585A=0.000585

The amount of substance will be present around in 2500 years is 0.000585 grams

4 0
11 months ago
The graph of g(x) is shown. Determine the transformations from the parent function f(x)=x2 to the new function g(x)=15x2+5
Viktor [21]

Answer:

The graph of g is translated down 5 units from the graph of f and stretched horizontally

Step-by-step explanation:

was correct on test :)

pls brainliest XD

.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.~.

7 0
2 years ago
You ask 200 randomly chosen students to name their favorite ice cream flavor. There are 1800 students in the school. Based on th
Kaylis [27]

Answer:

351

Step-by-step explanation:

Complete question :

Vanilla= 36

Chocolate=21

Strawberry=24

Chocolate Chip=39

SOLUTION:

39 chocolate chip to 200 students = x chocolate chip to 1800 students

39/200 = x / 1800

Solving for 'x'

(200)(x) = (39)(1800)

200x = 70200

x = 70200/200

x = 351

OR

39 out of 200 picked chocolate chip

therefore, 39/200 = 0.195 = 19.5%  ( 32.5% chose chocolate chip)

19.5% of 1800 = 0.195(1800) = 351 students

6 0
3 years ago
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