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kirill [66]
3 years ago
12

Consider the following argument:

Mathematics
1 answer:
mariarad [96]3 years ago
3 0

Answer:

r \Rightarrow p\\ q \Rightarrow p\\ r \vee p\\ (r \vee q) \Rightarrow \neg r\\ s

Step-by-step explanation:

r \Rightarrow p \equiv (\neg r \vee p), p is false.

q \Rightarrow p \equiv (\neg q \vee p), p is false.

(r \vee q), r and q are falses.

(r \vee q) \Rightarrow \neg r \equiv (\neg (r \vee q) \vee \neg r). this sentence is true.

s

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Find the sum of the first 9 terms of the following series, to the nearest integer.
Arturiano [62]
367 is the best answer I came up with
4 0
2 years ago
The answer is not A can someone plz help me I’m not understanding it thank you it would be appreciated
jeka94

nswer:

209.8

Step-by-step explanation:

the bottom is = 11 * 5

two of the sides are 11 * 9.3 / 2    because they are triangles, and then times 2 because there are two of them

the other two sides are 10.5 * 5 / 2 , and the * 2 because there are two of them again.

(11 * 5) + (11 * 9.3 * 2 / 2) + (10.5 * 5 * 2 / 2) =209.8

6 0
3 years ago
Abby earns $9.95 per hour doing landscape work. She worked 8.5 hours last week.
Salsk061 [2.6K]

Answer:

$84.58

Step-by-step explanation:

You would do 9.95 times 8.5 which gives you 84.575 which in money case you round to two decimal places you keep the 5 but 7 you round to 8 because "5 or more you add one more"

Hope this helps

8 0
2 years ago
Let f(x) = 2x+4. If f(x) = 16, find x.
jeyben [28]

f(x)=2x+4

And we are given that f(x)=16 and want to find the value of x. Set f(x) to 16 and we get the equation:

2x+4=16

Subtract both sides by 4

2x=12

Divide both sides by 2

x=6

This is the answer. Let me know if you need any clarifications, thanks!

8 0
3 years ago
Read 2 more answers
What are the fourth roots of 6+6√(3i) ?
Helen [10]

Answer:

Step-by-step explanation:

The genral form of a complex number in rectangular plane is expressed as z = x+iy

In polar coordinate, z =rcos ∅+irsin∅ where;

r is the modulus = √x²+y²

∅ is teh argument = arctan y/x

Given thr complex number z = 6+6√(3)i

r = √6²+(6√3)²

r = √36+108

r = √144

r = 12

∅ = arctan 6√3/6

∅ = arctan √3

∅ = 60°

In polar form, z = 12(cos60°+isin60°)

z = 12(cosπ/3+isinπ/3)

To get the fourth root of the equation, we will use the de moivres theorem; zⁿ = rⁿ(cosn∅+isinn∅)

z^1/4  = 12^1/4(cosπ/12+isinπ/12)

When n = 1;

z1 =  12^1/4(cosπ/3+isinn/3)

z1 = 12^1/4cis(π/3)

when n = 2;

z2 = 12^1/4(cos2π/3+isin2π/3)

z2 = 12^1/4cis(2π/3)

when n = 3;

z2 = 12^1/4(cosπ+isinπ)

z2 = 12^1/4cis(π)

when n = 4;

z2 = 12^1/4(cos4π/3+isin4π/3)

z2 = 12^1/4cis(4π/3)

8 0
3 years ago
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