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vladimir2022 [97]
2 years ago
10

Two similar triangular pastures meet at a

Mathematics
2 answers:
AnnZ [28]2 years ago
5 0
The answer is 600 for your question.
ratelena [41]2 years ago
3 0

Note that this is still a rectangle, and the length of the fencing is still 600 ft.

So the sum of the sides NOT along the river x + x + y = 600, and the area equals xy.

This makes the two equations: 2x + y = 600, and A = xy.

To find the largest area, we need to find A as a function of x or y. I suggest solving the first equation for y and replacing that in the second equation.

y = 600 - 2x. and A(x) = x(600-2x)

We now need to maximize A(x) = 600x - 2x2.

Remember, if x = -b/(2a), we find the x value of the vertex, the y value can be found by substitution.

So, since a = -2, and b = 600, x = -600/(-4) = 150 ft. If x = 150, y = 600 - 2(150) = 300.

So, the dimensions are 150 x 300 and the maximum area = 300(150) = 45,000 ft2

I hope this helps. By the way, there are many variations of this, and they are all similar. For example, you might want to make several pens with two lengths parallel and have three parallel withs inside.

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Answer: See explanation

Step-by-step explanation:

Here is the complete question:

A museum requires a minimum number of chaperones proportional to the number of students on a field trip. The museum requires a minimum of 3 chaperones for a field trip with 24 students. Which of the following could be combinations of values for the students and the minimum number of chaperones the museum requires? Choose 2 answers.

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We then divide the number of students given in the question by the number of chaperone to know our answers. This. Will be:

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Therefore, this is wrong.

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