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3 years ago

Two similar triangular pastures meet at a

Mathematics

2 answers:

AnnZ [28]3 years ago

5 0

The answer is 600 for your question.

ratelena [41]3 years ago

3 0

Note that this is still a rectangle, and the length of the fencing is still 600 ft.

So the sum of the sides NOT along the river x + x + y = 600, and the area equals xy.

This makes the two equations: 2x + y = 600, and A = xy.

To find the largest area, we need to find A as a function of x or y. I suggest solving the first equation for y and replacing that in the second equation.

y = 600 - 2x. and A(x) = x(600-2x)

We now need to maximize A(x) = 600x - 2x2.

Remember, if x = -b/(2a), we find the x value of the vertex, the y value can be found by substitution.

So, since a = -2, and b = 600, x = -600/(-4) = 150 ft. If x = 150, y = 600 - 2(150) = 300.

So, the dimensions are 150 x 300 and the maximum area = 300(150) = 45,000 ft2

I hope this helps. By the way, there are many variations of this, and they are all similar. For example, you might want to make several pens with two lengths parallel and have three parallel withs inside.

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2 years ago

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Answer:

$P(Same\ Bill) = \frac{1}{3}$

$P(Second$

$P(Both\ Even) = \frac{1}{9}$

$Pr(One\ Odd) = \frac{4}{9}$

$P(Sum < 10) = \frac{1}{3}$

Step-by-step explanation:

Given

$Bills: \$1, \$5, \$10$

$Selection = 2\ bills$

The sample space is as follows:

This implies that we construct possible outcome that Ebony selects a bill, returns the bill and then select another.

This means that there are possibilities that the same bill is selected twice.

So, the sample space is as follows:

$S = \{(1,1), (1,5), (1,10), (5,1), (5,5), (5,10), (10,1), (10,5), (10,10)\}$

$n(S) = 9$

Solving (a): $P(Same\ Bill)$

This means that the first and second bill selected are the same.

The outcome of this are:

$Same = \{(1,1),(5,5),(10,10)\}$

$n(Same\ Bill) = 3$

The probability is:

$P(Same\ Bill) = \frac{n(Same\ Bill)}{n(S)}$

$P(Same\ Bill) = \frac{3}{9}$

$P(Same\ Bill) = \frac{1}{3}$

Solving (a): $P(Second < First\ Bill)$

This means that the second bill selected is less than the first.

The outcome of this are:

$Second < First = \{(1,5), (1,10), (5,10)\}$

$n(Second < First) = 3$

The probability is:

$P(Second$

Solving (c): $P(Both\ Even)$

This means that the first and the second bill are even

The outcome of this are:

$Both\ Even = \{(10,10)\}$

$n(Both\ Even) = 1$

The probability is:

$P(Both\ Even) = \frac{n(Both\ Even)}{n(S)}$

$P(Both\ Even) = \frac{1}{9}$

Solving (e): $P(Sum < 10)$

This question has missing details.

The correct question is to determine the probability that, the sum of both bills is less than 10

The outcome of this are:

$One\ Odd = \{(1,10), (5,10), (10,1), (10,5)\}$

$n(One\ Odd) = 4$

The probability is:

$Pr(One\ Odd) = \frac{n(One\ Odd)}{n(S)}$

$Pr(One\ Odd) = \frac{4}{9}$

Solving (d): $P(One\ Odd)$

This question has missing details.

The correct question is to determine the probability that, exactly one of the bills is 0dd

The outcome of this are:

$Sum < 10 = \{(1,1), (1,5), (5,1)\}$

$n(Sum < 10) = 3$

The probability is:

$P(Sum < 10) = \frac{n(Sum < 10)}{n(S)}$

$P(Sum < 10) = \frac{3}{9}$

$P(Sum < 10) = \frac{1}{3}$

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3 years ago

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vodka [1.7K]

Answer:

Step-by-step explanation:

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156/13 = 12 so 1 liter gasoline is spent per 12 kilometers

So for 480 kilometers we would need 40 liter gasoline because

480/12 = 40

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2 years ago

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Crank

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3 years ago

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