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3 years ago

Solve 10(y+7)=12y for y

Mathematics

2 answers:

12345 [234]3 years ago

7 0

Answer:

y=35

Step-by-step explanation:

10(y+7)=12y

10y+70=12y

70=12y-10y

70=2y

70/2=y

35=y

therefore, y=35

astraxan [27]3 years ago

5 0

Answer:

y=35

Step-by-step explanation:

10(y+7)=12y

10xY and 10x7 which would be 10y+70=12y

subtract 10y from 12y= 2y

2y=70, divide 2 by 70 which equals 35.

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Last year the depth of the river was 4.2 feet deep. This year it dropped 25%. Find the depth of the river this year to cross it.

Novosadov [1.4K]

Answer:

The river is 3.15 feet deep.

Step-by-step explanation:

First let's recognize what we need to find: the depth of the river

We know last year the river was 4.2 feet deep, but it dropped 25%. This means we also need to find how much it dropped. To find this, we need to know what 25% of 4.2 is. Write an equation for this.

y = 25% of 4.2

y = 0.25 • 4.2

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This means that the river dropped 1.05 feet. To know its depth now, we need to subtract 1.05 from 4.2. Write an equation for this.

d = 4.2 - 1.05

d = 3.15

The river is 3.15 feet deep.

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3 years ago

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(a) Complete the table of values for y = 6 - 4x. Please help ❤️

shutvik [7]

Answer:

$\boxed{\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & 10& 6& 2&(-2)&-6 \\\cline{1-6}\end{tabular}}$

Step-by-step explanation:

Given equation to us is :-

$\implies y = 6 - 4x$

So , here we can put different values of x in order to get different values of y .

Initial table given to us is ,

$\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & & & 2&&-6 \\\cline{1-6}\end{tabular}$

Put x = (-1) :-

$\implies y = 6 - 4x \\\\\implies y = 6 -4(-1) \\\\\implies y = 6 + 4 \\\\\red{\bf\implies y = 10}$

Put x = 0 :-

$\implies y = 6 - 4x \\\\\implies y = 6-4(0) \\\\\implies y = 6 - 0 \\\\\pink{\bf\implies y = 6 }$

Put x = 2 :-

$\implies y = 6-4x \\\\\implies y = 6 - 4(2) \\\\\implies y = 6 - 8 \\\\\blue{\bf\implies y = (-2)}$

Hence the final table would be :- 

$\begin{tabular}{|c|c|c|c|c|c|}\cline{1-6} \bf x & -1 & 0&1&2&3\\\cline{1-6} \bf y & 10& 6& 2&(-2)&-6 \\\cline{1-6}\end{tabular}$

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3 years ago