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Reika [66]
3 years ago
9

The florida manatee population is 3,000 and is decreasing by 11% each year. Write a function for this situation.

Mathematics
2 answers:
True [87]3 years ago
5 0

Answer:

P=3000(0.89)^t

Step-by-step explanation:

It was given that, florida manatee population is 3,000 and is decreasing by 11% each year.

We want to write a function for this situation.

Since the population is decreasing annually, it is modelled by:

P=P_0(1-r\%)^t

We substitute the give initial population and rate of decrease to get:

P=3000(1-0.11)^t

This simplifies to:

P=3000(0.89)^t

noname [10]3 years ago
5 0

Answer:P_{(t)}=P_{o}(1-0.11)^{t}

Step-by-step explanation:

According to the described situation, the current manatee population is 3000, if it decreases 11\%=0.11 each year this means in one year the manatee population will be:

3000-(3000(0.11))=2671 (1)

And the next year:

2671-(2671(0.11))=2376.3 (2)

This mean each year the population will be 11\% less than last year.

So, in this case we can use the following function to express this decrease:

P_{(t)}=P_{o}(1+r)^{t} (3)

Where:

P_{(t)} Is the number of manaties at time t

P_{o}=3000 is the current number of manaties (this year)

r=-11\%=-0.11 is the decrease rate of the population

t is the time (in years)

For example, if we want to estimate the number of manaties for next year, t=1:

P_{(1)}=3000(1-0.11)^{1}

P_{(1)}=2670

If we want to estimate the number of manaties in two yeas, t=2:

P_{(2)}=3000(1-0.11)^{2}

P_{(2)}=2376.3

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The USDA conducted tests for salmonella in produce grown in California. In an independent sample of 252 cultures obtained from w
Marat540 [252]

Answer:

 The decision rule is  

Fail to reject the null hypothesis

  The conclusion is  

There no sufficient evidence to show that the proportion of salmonella in the region’s water differs from the proportion of salmonella in the region’s wildlife

Step-by-step explanation:

From the question we are told that

   The first  sample size is n_1   =  252

    The number that tested positive is  k_1  =  18

     The second sample size is  n_2   =  476

     The number that  tested positive is  k_2 =  20

     The level of significance is  \alpha  = 0.01

Generally the first sample proportion is mathematically represented as

      \^ p _1 =  \frac{k_1 }{ n_1 }

=>    \^ p _1 =  \frac{18 }{ 252 }

=>    \^ p _1 = 0.071

Generally the second sample proportion is mathematically represented as

      \^ p _2 =  \frac{k_2 }{ n_2 }

=>    \^ p _2 =  \frac{20 }{ 476}

=>    \^ p _2 = 0.042

The  null hypothesis is            H_o  :  p_1 - p_2 = 0

The alternative hypothesis is  H_a :  p_1 - p_2 \ne 0

Generally the test statistics is mathematically represented

       z =  \frac{ \^ p_1 - \^ p_2  -  ( p_ 1 - p_2 )}{ \sqrt{\frac{\^ p_1 (1-\^ p_1)}{ n_1  } + \frac{\^ p_2 (1-\^ p_2)}{ n_2  }  } }

=>    z =  \frac{ 0.071 - 0.042  - 0 }{ \sqrt{\frac{0.071  (1-0.071)}{  252  } + \frac{0.042 (1-\^ 0.042)}{ 476  }  } }

=>    z =  1.56

From the z table  the area under the normal curve to the right corresponding to  1.56   is  

        P(Z >  1.56 ) =0.05938

Generally the p-value is mathematically represented as

         p-value =  2 * P(Z >  1.56 )

=>      p-value = 2 *  0.05938

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From the value obtained we see that   p-value  >  \alpha hence

  The decision rule is  

Fail to reject the null hypothesis

  The conclusion is  

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2 years ago
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Step-by-step explanation:

<u>Given information</u>

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<u>Given formula</u>

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<u>Convert Kilogram unit to Gram</u>

1 kg = 1000 g

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<u>Substitute values into the given formula</u>

Total = Number of oranges × Average weight

Number of oranges = Total / Average weight

Number of oranges = 4500 / 75

<u>Simplify by division</u>

\Large\boxed{Number~of~oranges~=~60}

Hope this helps!! :)

Please let me know if you have any questions

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