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AfilCa [17]
3 years ago
15

The graph below shows the number of visitors at a theme park. How many more visitors in total went to the park in June, July and

August in Year 2 than Year 1?

Mathematics
1 answer:
Olin [163]3 years ago
8 0
From the information given by the graph

Year 1 visitors
June = 9450
July = 9500
August = 9600

Year 2 visitors
June = 9450
July = 9600
August = 9800

Total visitor Year 1 = 9450 + 9500 + 9600 = 28550
Total visitor Year 2 = 9450 + 9600 + 9800 = 28850

Visitor in Year 2 is 28850-28550 = 300 more than visitor in Year 1
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Help please :/<br> Our teacher wants us to solve a puzzle, but I have no idea what's going on
mote1985 [20]

Answer:

Oh, I done this before

Step-by-step explanation:

you have to find the least valur and put it to least to greatest!

MArk me brianliest!

7 0
3 years ago
A little help Mean median mode range
goldenfox [79]

Answer:

Mean, median, and mode are three kinds of "averages". There are many "averages" in statistics, but these are, I think, the three most common, and are certainly the three you are most likely to encounter in your pre-statistics courses, if the topic comes up at all.

The "mean" is the "average" you're used to, where you add up all the numbers and then divide by the number of numbers. The "median" is the "middle" value in the list of numbers. To find the median, your numbers have to be listed in numerical order from smallest to largest, so you may have to rewrite your list before you can find the median. The "mode" is the value that occurs most often. If no number in the list is repeated, then there is no mode for the list.

Mean, Median, Mode, and Range

The "range" of a list a numbers is just the difference between the largest and smallest values.

   Find the mean, median, mode, and range for the following list of values:

13, 18, 13, 14, 13, 16, 14, 21, 13

The mean is the usual average, so I'll add and then divide:

(13 + 18 + 13 + 14 + 13 + 16 + 14 + 21 + 13) ÷ 9 = 15

Note that the mean, in this case, isn't a value from the original list. This is a common result. You should not assume that your mean will be one of your original numbers.

The median is the middle value, so first I'll have to rewrite the list in numerical order:

13, 13, 13, 13, 14, 14, 16, 18, 21

There are nine numbers in the list, so the middle one will be the (9 + 1) ÷ 2 = 10 ÷ 2 = 5th number:

13, 13, 13, 13, 14, 14, 16, 18, 21

So the median is 14.

The mode is the number that is repeated more often than any other, so 13 is the mode.

The largest value in the list is 21, and the smallest is 13, so the range is 21 – 13 = 8.

mean: 15

median: 14

mode: 13

range: 8

Note: The formula for the place to find the median is "([the number of data points] + 1) ÷ 2", but you don't have to use this formula. You can just count in from both ends of the list until you meet in the middle, if you prefer, especially if your list is short. Either way will work.

Step-by-step explanation:

4 0
3 years ago
Of 136 randomly selected adults, 33 were found to have high blood pressure. Construct a 95% confidence interval for the true of
navik [9.2K]

Answer:

The 95% confidence interval of the proportion of all adults that have high blood pressure is 0.17059 < \hat{p} < 0.314695

Step-by-step explanation:

The confidence interval for a proportion is given by the following formula;

CI=\hat{p}\pm z\times \sqrt{\frac{\hat{p}(1-\hat{p})}{n}}

Where:

x = 33

n = 136

\hat{p} = x/n = 33/136 = 0.243

z value for 95% confidence is 1.96

Plugging in the values, we have;

CI=0.243\pm 1.96\times \sqrt{\frac{0.243(1-0.243)}{136}}

Which gives;

0.17059 < \hat{p} < 0.314695

Hence the 95% confidence interval of the proportion of all adults that have high blood pressure = 0.17059 < \hat{p} < 0.314695

From the above we have;

23.2 < x < 42.798

Since we are dealing with people, we round down as follows;

23 < x < 42.

4 0
3 years ago
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hodyreva [135]

Answer: that the solution is true

Step-by-step explanation: if you get something like 10=10 it’s true but if you get like 4= 7 it’s false

4 0
3 years ago
Find the domain of the function.
timurjin [86]

When taking square roots, you can't take square roots of negative roots of negative numbers. So, what will work for the domain of u(x) is what makes u(x) zero or more. We can make an inequality for that.

u(x) ≥ 0.

\sqrt{9x+27} \geq  0

9x + 27 ≥ 0 by squaring both sides

9x ≥ -27

x ≥ -3

So the domain of the function is when x ≥ -3 is true.

5 0
4 years ago
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