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wolverine [178]
3 years ago
9

Please help me!!!! ‼️

Mathematics
1 answer:
scoray [572]3 years ago
6 0

Answer:

$300.25

Step-by-step explanation:

Because $550.75 - $105 - $45.50 - $100 = $300.25

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Carlos is analyzing the results of an experiment on two groups of mice in which he compared the difference in their weight gain
Arlecino [84]
Given:difference in the mean weight gain is 0.60 gramsstandard deviation of the difference in sample mean is 0.305
68% confidence interval for the population mean difference is a) 0.305
0.60 + 1 * 0.3050.60 + 0.305 = 0.9050.60 - 0.305 = 0.295
95% confidence interval for the population mean difference is c) 0.61
0.60 + 2 * 0.3050.60 + 0.61 = 1.210.60 - 0.61 = -0.01

3 0
3 years ago
2. It’s time for Ronda to start repaying her student loans, which are amortized over the next 10 years. Her first month’s paymen
grigory [225]

Based on the amount that she paid in the first month, the amount Ronda will pay for the next month is<u> $396.</u>

When a loan is amortized, it means that one can pay it off by paying the same amount every period until they would have paid off both the loan and the associated interest.

The amortized amount contains:

  • A portion going towards the principal(debt )
  • A portion going towards the interest accumulated.

In conclusion, as the amount is the same every time, Ronda will have to pay the same amount of $396 the next month.

<em>Find out more at brainly.com/question/12256592. </em>

7 0
3 years ago
Workings please......
attashe74 [19]

Answer:

21.142

Step-by-step explanation:

not sure it's correct

3 0
3 years ago
Simplify the expressions<br> (a^2b^-3/a^-2b^2)^2
poizon [28]

Answer:

(\frac{a^{2}b^{-3}  }{a^{-2}b^{2}  })^{2}  = (a^{2-(-2) }b^{-3 - 2})^{2} \\ = (a^{4}b^{-5} )^{2}  = (a^{4})^{2} (b^{-5})^{2}  = a^{8}  b^{-10}

Here is for you.

Step-by-step explanation:

6 0
3 years ago
Multiply and simplify the following complex numbers:<br> (-3 - 2i) x (-4 + 2i)
Alja [10]
(-3 - 2i) x (-4+ 2i) if you simplify using FOIL you will get 16+2i
5 0
3 years ago
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