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Aleks [24]
2 years ago
11

Can someone assist me with this, I'm having problems with this

Mathematics
1 answer:
nirvana33 [79]2 years ago
8 0
It’s true!! Hope this helped!!!!
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Less for statement 1 and less for statement 2
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or security​ reasons, a company will enclose a rectangular area of 11,200 m2 in the rear of its plant. One side will be bounded
pychu [463]

The dimensions of the rectangle are 150 m and 75 m respectively.

Let x be the length of the rectangular area and y be the width of the rectangular area.

Its area A = xy

Given that its area is 11,000 m², xy = 11000 m² (1)

Also, since the bounding side of the building is 150 m long and the fencing is 300 m, the perimeter of the rectangular area is P = 150 m + 300 m = 450 m.

Also, the perimeter of the rectangular area is P = 2(x + y)

Since P = 450 m

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x + y = 225 m (2)

Since the bounding side of the building represents one dimension of the rectangle, x = 150 m.

Substituting x into (2), we get the other dimension

x + y = 225

150 + y = 225

y = 225 m - 150 m

y = 75 m

So, the dimensions of the rectangle are 150 m and 75 m respectively.

Learn more about dimensions of a rectangular area here:

brainly.com/question/16818606

4 0
2 years ago
Solve 2(1 - x) &gt; 2x.<br><br>a.) O x &lt; 0.5<br>b.) Ox&gt; 2<br>c.) Ox&lt;2<br>d.) O x &gt; 0.5​
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a) Ox<0.5 wjsjdhdjdjdj

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3 years ago
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How many cups are in 4 feet
Oksanka [162]

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A person who is 6 feet tall has a 2 foot shadow, while a telephone pole has a 16 foot long shadow. How tall is the telephone pol
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2*3=6

Multiply 3 to 16.

3*16= 48

The pole is 48 feet long.

I hope this helps!
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3 years ago
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