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telo118 [61]
3 years ago
7

Help me please Love you, thanks!!!

Mathematics
2 answers:
balu736 [363]3 years ago
8 0

Answer:

Neither for 1

the second option for 2

Step-by-step explanation:

not sure how to explain this

harkovskaia [24]3 years ago
7 0
1: neither
2: b (second option)
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Use a Double- or Half-Angle Formula to solve the equation in the interval [0, 2π). (Enter your answers as a comma-separated list
lara31 [8.8K]
Sin(2θ)+sin(<span>θ)=0
use double angle formula: sin(2</span>θ)=2sin(θ)cos(<span>θ).
=>
2sin(</span>θ)cos(θ)+sin(<span>θ)=0
factor out sin(</span><span>θ)
sin(</span>θ)(2cos(<span>θ)+1)=0
by the zero product property,
sin(</span>θ)=0 ...........(a) or
(2cos(<span>θ)+1)=0.....(b)
Solution to (a): </span>θ=k(π<span>)
solution to (b): </span>θ=(2k+1)(π)+/-(π<span>)/3
for k=integer

For [0,2</span>π<span>), this translates to:
{0, 2</span>π/3,π,4π/3}
8 0
3 years ago
A(b + 8) = ab + __<br> Answer?
stiv31 [10]

Answer:

ab + <u>8a</u>

Step-by-step explanation:

a(b + 8)

~Distribute

ab + a8

~Reorder

ab + 8a

Best of Luck!

5 0
3 years ago
Read 2 more answers
Marta walked at 4.9 miles per hour for 0.95 hours. how far did she walk
BartSMP [9]

Answer:

she walked 4.65 miles

Step-by-step explanation:

4.9 × 0.95

6 0
3 years ago
For this problem, assume that three students are chosen from 5 freshmen, 4 sophomores, and 4 juniors.
Sati [7]

The formula C(n, r)= \frac{n!}{r!(n-r)!}, where r! is 1*2*3*...r

is the formula which gives us the total number of ways of forming groups of r objects, out of n objects.

for example, given 10 objects, there are C(10,6) ways of forming groups of 6, out of the 10 objects.


<span>The sample space S in our problem is as follows: </span>

triples selected from 5 freshmen, 4 sophomores, and 4 juniors, so that at least 1 freshman is selected.

The selection of 1 freshman can be done in 5 ways. The selection of the remaining 2 out of 4 freshmen (one is already chosen), 4 sophomores, and 4 juniors can be done in C(12, 2) many ways.

C(12, 2)=\displaystyle{  \frac{12!}{2!10!}= \frac{12\cdot11\cdot10!}{2!10!}=66

So there are in total, 5*66= 330 possible triples.

n(S)=330


The event E "selecting 2 freshmen and 1 junior" can occur in :

C(5, 2)\cdot 4=\displaystyle{ \frac{5!}{2!3!}\cdot4=40 many ways.


so n(E)=40


P(E)=n(E)/n(S)=40/330=0.12



Answer: 0.12


 

4 0
4 years ago
Explain how you know 3 exponent 4 is equal to 9 exponent 2 without calculating the values?? Explain it with words......
miskamm [114]

Answer:

see explanation

Step-by-step explanation:

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3 0
3 years ago
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