<span>erry starts rowing at 2 pm from the west end of the lake, and Tao starts rowing from the east end of the lake at 2:05 pm.
------
Terry DATA:
rate = 60 meter/min ; time = x min ; distance = r*t = 60x meters
-----
Tao DATA:
rate = 40 meter/min ; time = x-5 min ; distance = r*t = 40(x-5) meters
--------------------------
If they always row directly towards each other at what time will the two meet?
------
Equation:
dist + dist = 2000 meters
60x + 40(x-5) = 2000
20x = 1800
x = 90 minutes
---</span>
This is probably the answer I’m not 100% sure
Answer:
Option (c) is correct.
Step-by-step explanation:
Given equation is :
The equation can be solved for a as follows :
Step 1.
Cross multiply the given equation
Step 2.
Now subtract b on both sides
3s-b = a+b+c-b
3s-b = a+c
Step 3.
Subtract c on both sides
3s-b-c=a+c-c
⇒ a=3s-b-c
The statement that is true for Darpana is " In step 3, she needed to subtract c rather than divide".
Answer:
m∠3 = 56
Step-by-step explanation:
Let's solve for x, first:
x + 9 = 3x - 85
9 = 2x - 85
94 = 2x
94/2 = x
47 = x
Now that we have x-value, we can substitute it in any one of the given equation to find angle 3 since, angle 1, 7 and 3 all are congruent:
=> m∠7 = x + 9
=> m∠7 = 47 + 9
=> m∠7 = 56
Since m∠7 ≅ m∠3
and m∠7 = 56, then
<u>m∠3 = 56</u>
Hope this helps!
Answer:
DE ≈ 14.91
Step-by-step explanation:
Make use of the relationships between sides and angles in a right triangle. These are summarized by the mnemonic SOH CAH TOA:
Sin = Opposite/Hypotenuse
Cos = Adjacent/Hypotenuse
Tan = Opposite/Adjacent
__
The side DE is opposite the angle 19°, so the sine or tangent relation will be involved. The sine relation requires you know hypotenuse EF. The tangent relation requires you know adjacent side DF.
The only common side between triangles CDF and DEF is side DF. That side is opposite the given 61° angle. The given side length (CF = 24) is adjacent to the 61° angle.
This means you have enough information to use these relations:
tan(61°) = DF/CF = DF/24
DF = 24·tan(61°)
and
tan(19°) = DE/DF
DE = DF·tan(19°) = (24·tan(61°))·tan(19°) . . . . . use DF from above
DE ≈ 24(1.804048)(0.344328) ≈ 14.908
The length of DE is about 14.91.
