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3 years ago

Stoplight Auto Center is selling its shares for 28 3/4. What would be the cost of 90 shares?

Mathematics

1 answer:

Stells [14]3 years ago

8 0

Answer: $2,587.50 for 90 shares

Step-by-step explanation:

(28 3/4)(90) = 2,587 1/2

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I want to know the answer to the sum of f and 6

11111nata11111 [884]

f + 6 = ?

Well, the answer can be pretty much any number. It all depends on what number f is. f is a variable, so you can plug in any number to replace f.

For example, if f was 5, this is what the equation would look like:

5 + 6 = 11

If f was -3, this is what the equation would look like:

-3 + 6 = 3

So, again, the answer can be anything. It depends on what f is.

4 0

3 years ago

Maurice spent 1/2 of his money on lunch. He had 2.50 left.<br> How much money did he start with?

OverLord2011 [107]

Answer:

5.0

Step-by-step explanation:

1÷2=2.5

1=2.50×2

=5.0

6 0

3 years ago

Is compound interest always greater than simple interest ?Give examples

g100num [7]

Yes compund interest is always greater than simple interest

simple interest = principal

compound interest = principal + accumulated interest

3 0

3 years ago

Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notic

Free_Kalibri [48]

The equation for the situation is $y=200(\frac{2}{3})^{x}$

It will take around 9 years for her to have around 5 sheep

Step-by-step explanation:

The exponential decay growth/decay equation is $y=a(b)^{x}$ , where

a is the initial value
b is the growth/decay factor
If b > 1, then it is a growth factor
If 0 < b < 1, then it is a decay factor

Erica is a sheep farmer. She is having a problem with wolves attacking the flock. She starts with an initial 200 sheep and notices that the population is two-thirds of the previous year

∵ The population is decreased

∴ The equation is decay

∵ The population is two-thirds of the previous year

∴ The decay factor is $\frac{2}{3}$

∵ She starts with an initial 200 sheep

∴ the initial value is 200

∵ The decay equation is $y=a(b)^{x}$ , where y represent the

population in x years

∵ a = 200

∵ b = $\frac{2}{3}$

∴ $y=200(\frac{2}{3})^{x}$

The equation for the situation is $y=200(\frac{2}{3})^{x}$

∵ The population after x years is around 5 sheep

- Substitute y by 5 to find x

∵ $5=200(\frac{2}{3})^{x}$

- Divide both sides by 200

∴ $0.025=(\frac{2}{3})^{x}$

- Insert ㏒ for both sides

∴ $log(0.025)=log(\frac{2}{3})^{x}$

∴ $log(0.025)=xlog(\frac{2}{3})$

- Divide both sides by $log(\frac{2}{3})$

∴ 9.098 = x

∴ x is around 9 years

It will take around 9 years for her to have around 5 sheep

Learn more:

You can learn more about the equation in brainly.com/question/10666510

#LearnwithBrainly

8 0

3 years ago

An equation of the line that passes through (3, 1) and (0, 10).

MrMuchimi

Answer:

So the equation of the line that passes through (3, 1) and (0, 10) is y=-3x+10

Step-by-step explanation:

(3, 1) and (0, 10)

m=y²-y¹/x²-x¹

m=10-1/0-3

m=9/-3

m=-3

y=mx+b

y-y=m(x-x1)

y-1=-3(x-3)

y-1=-3x+9

+1 +1

y=-3x+10

3 0

3 years ago