Answer:
40 drops
Approximately 0.166 %
Step-by-step explanation:
It would be easier to work the same units for volume
Since there are 1000 ml in a liter
Original water volume 1.2 L = 1.2 x 1000 = 1200 mLl
The final volume of the acid-water solution = 1.202 L = 1202 mL
So total volume of acid added = 1202-1200 = 2 mL
Each drop of acid is 0.05 mL
Number of drops added = 2/.05 = 40 drops
Percent of acid in acid solution = (Volume of acid added)/(Final volume) x 100 = (2/1202) ≈ 0.00166 x 100 ≈ 0.166 %
Answer:
A
Step-by-step explanation:
0 is sea lvl so just add and subsubtract
Answer:
<em>f(x) = x² (2+i)x-15-3i</em>
Step-by-step explanation:
Since the zeros of the equation are -3 and 5+i, hence the factors of the polynomial in x is (x+3) and (x-(5+i))
Multiplying both factors
f(x) = (x+3)(x-(5+i))
f(x) = (x²-(5+i)x+3x -3(5+i))
f(x) = x² - (5+i- 3)x -15-3i
f(x) = x² (2+i)x-15-3i
<em>hence the required polynomial function in x is f(x) = x² (2+i)x-15-3i</em>
Answer:
x = 1/6
Step-by-step explanation:
hope it helps.
x= 1/6
