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KonstantinChe [14]
2 years ago
9

Iris wants to buy sneakers at $15 each and high heels at $30 each. Write an algebraic expression to find the total cost of the s

hoes if she buys x sneakers and y high heels. Write your answer in the form “ax + by” where a and b are positive or negative constants.
Mathematics
1 answer:
kogti [31]2 years ago
5 0

Answer: 30y + 15x

If x is for sneakers, and y is for high heels, plug 15 in for a and 30 in for b. This means that x is how many sneakers she buys, and y is how many high heels she buys. The equation altogether represents the total amount of her purchases.

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Answer:

13.44 or 13 11/25 hours

Step-by-step explanation:

First use this format: number of essays/hours

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50/7 + 50/14 + 25/6 = 200/x

Second, solve:

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300/42 + 150/42 + 175/6 = 200/x

625/42 = 200/x

- cross-multiply

625x = 8,400

x = 336/25 = 13 11/25 = 13.44 (any one of these answers would work)

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3 years ago
When 2 less than 3 lots of a number is doubled the result is 5
Ksivusya [100]
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Step-by-step explanation:

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Air pressure may be represented as a function of height (in meters) above the
denis-greek [22]

Answer: OPTION C.

Step-by-step explanation:

<h3> The complete exercise is: "Air pressure may be represented as a function of height (in meters) above the surface of the Earth, as shown below:</h3><h3>  P(h) =P_0e^{-0.00012h} </h3><h3> In this function P_o   is the air pressure at the surface of the earth, and h is the height above the surface of the Earth, measured in meters. At what height will the air pressure equal 50% of the air pressure at the surface of the Earth"</h3><h3></h3>

Given the following function:

P(h) =P_0e^{-0.00012h}

In order to calculate at what  height the air pressure will be equal 50% of the air pressure at the surface of the Earth, you can follow these steps:

1. You need to substitute P(h)=0.5P_o into the function:

0.5P_o=P_0e^{-0.00012h}

2. Finally, you must solve for h.

Remember the following property of logarithms:

ln(b)^a=a*ln(b)\\\\ln(e)=1

Then, you get this result:

0.5P_o=\frac{P_o}{e^{0.00012h}}\\\\(0.5P_o)(e^{0.00012h})=P_o\\\\e^{0.00012h}=\frac{P_o}{0.5P_o}\\\\ln(e)^{0.00012h}=ln(2)\\\\0.00012h*1=ln(2)\\\\h=\frac{ln(2)}{0.00012}\\\\h=5576.2

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