Point A shows that she is incorrect.
With functions, you can perform the "straight line test through each point. If the line goes through both points, you know it's not a function.
If we plotted point A, it'd fail the straight line test because the given point (-6, 7) already has -6 as an x value.
Hope this helps!
Step-by-step explanation:
Find negative square root of 16. (4 points) a −4 b 4 c ±4 d −8
"A quadrilateral with both pairs of opposite sides parallel and all sides the same length, i.e., an equilateral parallelogram."
Answer:
0
Step-by-step explanation:
1) Multiply the first equation by -3: -6x - 3y = 12
2) Substitute 2x + 12 for -3y in the above equation, obtaining:
-6x + 2x + 12 = 12
Then -4x = 0, and x = 0. Letting x = 0 in the first equation, we get:
0 + y = -4, so y = -4.
The x-value at the intersection of the lines is zero (0).
That intersection is at (0, -4).
