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3 years ago

Find the area of the shaded region. The graph depicts the standard normal distribution with mean 0 and standard deviation 1

Mathematics

1 answer:

Digiron [165]3 years ago

8 0

Answer:

$P(z$

And the best option would be:

$0.8708$

Step-by-step explanation:

We assume that the distribution for the random variable is:

$X \sim N (\mu=0 , \sigma=1)$

For this case we want to calculate the following probability:

$P(z$

And we can use the normal standard distribution or excel and we got:

$P(z$

And the best option would be:

$0.8708$

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What is the domain of this graph?

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A. Whole numbers from 0 to 10

The domain is composed of all x value on the graph. Every point is on a whole number for x.

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3 years ago

50(1.05)t < 100 how much growth or decay

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$50(1.05)t \ \textless \ 100$

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3 years ago

Triangle N Q L has centroid S. Lines are drawn from each point through the centroid to the midpoint of the opposite side to form

Doss [256]

Answer:

Step-by-step explanation:

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3 years ago

Read 2 more answers

The authors of a paper presented a correlation analysis to investigate the relationship between maximal lactate level x and musc

ArbitrLikvidat [17]

Answer:

a) Sample correlation coefficient, r = 0.7411

bi) test statistic, t = 4.102

bii) P-value = 0.000736

Step-by-step explanation:

a) The formula for the sample correlation coefficient is given by the formula:

$r = \frac{S_{xy} }{\sqrt{S_{xx} S_{yy} }} }$

$S_{xx} = 2,648,130.357\\S_{yy} = 36.7376,\\S_{xy} = 7408.225$

$r = \frac{7408.225}{\sqrt{2648130.357*36.7376} }$

r = 0.7511

i) formula for the test statistic is given by the formula:

$t = \frac{r\sqrt{n-1} }{\sqrt{1 - r^{2} } }$

sample size, n = 4

$t = \frac{0.7511\sqrt{14-1} }{\sqrt{1 - 0.7511^{2} } }$

t = 4.102

ii) Degree of freedom, df = n -2

df = 14 -2

df = 12

The P-value is calculate from the degree of freedom and the test statistic using excel

P-value =(=TDIST(t,df,tail))

P-value = (=TDIST(4.1,12,1)

P-value = 0.000736

4 0

3 years ago

On the first play during the football game our team gained 5 yards. Between both the second and third play our team lost eight y

Maurinko [17]

Answer:

loss

Step-by-step explanation:

you might want to check someone else answer first tho

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3 years ago