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3 years ago

Find the area of the shaded region. The graph depicts the standard normal distribution with mean 0 and standard deviation 1

Mathematics

1 answer:

Digiron [165]3 years ago

8 0

Answer:

$P(z$

And the best option would be:

$0.8708$

Step-by-step explanation:

We assume that the distribution for the random variable is:

$X \sim N (\mu=0 , \sigma=1)$

For this case we want to calculate the following probability:

$P(z$

And we can use the normal standard distribution or excel and we got:

$P(z$

And the best option would be:

$0.8708$

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The steps in the heating of water in a pot kept on a stove are listed below:

butalik [34]

Answer

Step 1 and step 2

Step by step explanation

Heat can be transferred from one place to another place.

When pot kept on a stove, the heat from flame travels to the base of the pot, then heat travels from the base to the water.

Step 1: Heat from the flame travels to the base of the pot.

Step 2: Heat from the base of the pot travels to the water near its base.

Answer: C) Step 1 and Step 2

4 0

3 years ago

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Question 16 (Essay Worth 7 points) Verify the identity. tan (x + π/2) = -cot x

Rus_ich [418]

Step-by-step explanation:

We know that tan=sin/cos, so tan(x+π/2)=

$\frac{sin(x+pi/2)}{cos(x+pi/2)}$

Then, we know that sin(u+v)=sin(u)cos(v)+cos(u)sin(v),

so our equation is then

$\frac{sin(x)cos(\pi/2)+cos(x)sin(\pi/2)}{cos(x+\pi/2)} = \frac{cos(x)}{cos(x+\pi/2) }$

Then, cos(u+v)=cos(u)cos(v)-sin(u)sin(v), so our expression is then

$\frac{cos(x)}{cos(x)cos(\pi/2)-sin(x)sin(\pi/2)} = \frac{cos(x)}{-sin(x)} = -cot(x)$

6 0

2 years ago

6. If the net investment function is given by

Pachacha [2.7K]

The capital formation of the investment function over a given period is the

accumulated capital for the period.

(a) The capital formation from the end of the second year to the end of the fifth year is approximately 298.87.

(b) The number of years before the capital stock exceeds $100,000 is approximately 46.15 years.

Reasons:

(a) The given investment function is presented as follows;

$I(t) = 100 \cdot e^{0.1 \cdot t}$

(a) The capital formation is given as follows;

$\displaystyle Capital = \int\limits {100 \cdot e^{0.1 \cdot t}} \, dt =1000 \cdot e^{0.1 \cdot t}} + C$

From the end of the second year to the end of the fifth year, we have;

The end of the second year can be taken as the beginning of the third year.

Therefore, for the three years; Year 3, year 4, and year 5, we have;

$\displaystyle Capital = \int\limits^5_3 {100 \cdot e^{0.1 \cdot t}} \, dt \approx 298.87$

The capital formation from the end of the second year to the end of the fifth year, C ≈ 298.87

(b) When the capital stock exceeds $100,000, we have;

$\displaystyle \mathbf{\left[1000 \cdot e^{0.1 \cdot t}} + C \right]^t_0} = 100,000$

Which gives;

$\displaystyle 1000 \cdot e^{0.1 \cdot t}} - 1000 = 100,000$

$\displaystyle \mathbf{1000 \cdot e^{0.1 \cdot t}}} = 100,000 + 1000 = 101,000$

$\displaystyle e^{0.1 \cdot t}} = 101$

$\displaystyle t = \frac{ln(101)}{0.1} \approx 46.15$

The number of years before the capital stock exceeds $100,000 ≈ 46.15 years.

Learn more investment function here:

brainly.com/question/25300925

6 0

2 years ago

What is quantitative reasoning

AleksAgata [21]

Using math skills to answer a question

5 0

2 years ago

How manet times dose 50 go into 1,000

strojnjashka [21]

Answer:

20 times

Step-by-step explanation:

1,000 divided by 50 will be 20 try using lone division :)

6 0

3 years ago

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