The equation, in point-slope form, of the line that is parallel to the given line and passes through the point is y - 1 = 3/2(x+3)
<h3>Equation of a line</h3>
A line is the distance between two points. The equation of a line in point-slope form is expressed as:
y - y0 = m(x-x0)
Given the coordinates (-2, -4) and (2, 2) on the line, the slope is expressed as:
Slope = 2-(-4)/2-(-2)
Slope = (6)/4
Slope = 3/2
Find the equation of the line
y -(1) = 3/2(x-(-3))
y - 1 = 3/2(x+3)
Hence the equation, in point-slope form, of the line that is parallel to the given line and passes through the point is y - 1 = 3/2(x+3)
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B. -14
C. 12
D. 0
Hopefully this is right!
Answer:
g(x) = e^(x + 2) + 2
Step-by-step explanation:
First, let's describe the shifts.
Vertical shift.
For a function f(x), a vertical shift of N units is written as:
g(x) = f(x) + N
If N is positive, then the shift is upwards.
If N is negative, then the shift is downwards.
Horizontal shift.
For a function f(x), a horizontal shift of N units is written as:
g(x) = f(x - N)
If N is positive, the translation is to the right
If N is negative, the translation is to the left.
Now let's solve the question.
f(x) = e^x
First, we have a vertical shift up of 2 units, then:
g(x) = f(x) + 2
Now we have a shift to the left of 2 units:
g(x) = f(x - (-2)) + 2
g(x) = f(x + 2) + 2
Then:
g(x) = e^(x + 2) + 2
Answer:
Arc length XPY =28.26 m.
Step-by-step explanation:
Given : A circle with two arc XY and XPY and radius 6 m.
To find : Arc length XPY.
Solution : We have given that arc XY and XPY .
Radius = 6 m.
Central angle formed by arc XPY = 360 - 90 = 270.
Arc length = 2 *pi* r ( 
.
Plugging the values
Arc length = 2 *3.14 * 6 ( 
.
Arc length =37.68 ( 
.
Arc length =37.68 * 0.75
Arc length XPY =28.26 m.
Therefore, Arc length XPY =28.26 m.
