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2 years ago

12

You borrowed $59,000 for 2 years at 11% which was compounded annually. What

1 answer:

gayaneshka [121]2 years ago

6 0

Answer:

$72693.9

Step-by-step explanation:

To get this answer you need to use the compound interest formula, which will be A=P(1+r/n)^n(t). P=59,000 r=11%=0.11 n=1 (annually) t=2 years. From there you should be able to figure the rest out and get the answer. Hope this helps!

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PLEASE HELP!!! WILL REWARD BRAINLIEST!!!

jonny [76]

Answer:

The approximate monthly rate of growth is 1.24%

Step-by-step explanation:

we have the future value formula

$F=P(1+r)^t$

we have

$r=16\%=16/100=0.16$ ----> annual interest rate

so

$F=P(1+0.16)^t$

$F=P(1.16)^t$

Find the approximate monthly rate of growth

Remember that

$1\ year=12\ months$

so

Divide the number of periods t by 12

$F=P(1.16)^{\frac{t}{12}}$

Applying power rules property

$F=P(1.16^\frac{1}{12})^t$

$F=P(1.0124)^t}$

$1.0124-1=0.0124$

Convert to percentage

$0.0124*100=1.24\%$

therefore

The approximate monthly rate of growth is 1.24%

6 0

3 years ago

Pls answer me this all question

Scorpion4ik [409]

Answer:

a. $5 \frac{21}{40}$

b. $\frac{1}{42}$

Step-by-step explanation:

$a. \: 12 \frac{2}{5} - 6 \frac{7}{8}$

$\frac{62}{5} - \frac{55}{8}$

$\frac{62}{8} \times \frac{8}{8} - \frac{55}{8} \times \frac{5}{5}$

$\frac{62 \times 8 - 55 \times 5}{40}$

$\frac{221}{40}$

$5 \frac{21}{40}$

$b. \: \frac{3}{14} - \frac{4}{21}$

$\frac{3}{14} \times \frac{3}{3} - \frac{4}{21} \times \frac{2}{2}$

$\frac{3 \times 3}{42} - \frac{4 \times 2}{42}$

$\frac{1}{42}$

Hope it is helpful....

5 0

2 years ago

Read 2 more answers

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Flura [38]

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3 years ago

A number is chosen at random from 1 to 50. find the probability of selecting numbers greater than 3 and less than 39. How to sol

liq [111]

Solve than first chose letter and bind

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2 years ago

Answer ASAP: What is the set of the four consecutive integers, the largest of which is -234?

Elza [17]

I’m pretty sure the answer is -237, -236, -235, and -234. Because -234 would be the greatest of that consecutive set.

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3 years ago