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Elis [28]
3 years ago
5

WILL GIVE BRAINLIEST! PLEASE HELP I'm doing an exam!! A photograph is reduced by a scale factor of 3/4. If the original length o

f the photograph was 18 inches, what is the length of the reduced photo? My test is over in 10 mins :( Pls anyone.
4.5 inches


13.5 inches


15 inches


17 1/4 inches
Mathematics
1 answer:
Harlamova29_29 [7]3 years ago
4 0
13.5 inches, because if you add 4.5x4 or 9x2 it equals 18, then you just subtract 4.5 from 18 and it’s 13.5
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krek1111 [17]

Answer:

x=36

Divide the corresponding side (16) by 4/7

3 0
1 year ago
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Consider the following initial-value problem. (x + y)2 dx + (2xy + x2 − 2) dy = 0, y(1) = 1 Let ∂f ∂x = (x + y)2 = x2 + 2xy + y2
IRISSAK [1]

(x+y)^2\,\mathrm dx+(2xy+x^2-2)\,\mathrm dy=0

Suppose the ODE has a solution of the form F(x,y)=C, with total differential

\dfrac{\partial F}{\partial x}\,\mathrm dx+\dfrac{\partial F}{\partial y}\,\mathrm dy=0

This ODE is exact if the mixed partial derivatives are equal, i.e.

\dfrac{\partial^2F}{\partial y\partial x}=\dfrac{\partial^2F}{\partial x\partial y}

We have

\dfrac{\partial F}{\partial x}=(x+y)^2\implies\dfrac{\partial^2F}{\partial y\partial x}=2(x+y)

\dfrac{\partial F}{\partial y}=2xy+x^2-2\implies\dfrac{\partial^2F}{\partial x\partial y}=2y+2x=2(x+y)

so the ODE is indeed exact.

Integrating both sides of

\dfrac{\partial F}{\partial x}=(x+y)^2

with respect to x gives

F(x,y)=\dfrac{(x+y)^3}3+g(y)

Differentiating both sides with respect to y gives

\dfrac{\partial F}{\partial y}=2xy+x^2-2=(x+y)^2+\dfrac{\mathrm dg}{\mathrm dy}

\implies x^2+2xy-2=x^2+2xy+y^2+\dfrac{\mathrm dg}{\mathrm dy}

\implies\dfrac{\mathrm dg}{\mathrm dy}=-y^2-2

\implies g(y)=-\dfrac{y^3}3-2y+C

\implies F(x,y)=\dfrac{(x+y)^3}3-\dfrac{y^3}3-2y+C

so the general solution to the ODE is

F(x,y)=\dfrac{(x+y)^3}3-\dfrac{y^3}3-2y=C

Given that y(1)=1, we find

\dfrac{(1+1)^3}3-\dfrac{1^3}3-2=C\implies C=\dfrac13

so that the solution to the IVP is

F(x,y)=\dfrac{(x+y)^3}3-\dfrac{y^3}3-2y=\dfrac13

\implies\boxed{(x+y)^3-y^3-6y=1}

5 0
2 years ago
PLEASE HELP!!!!<br><br> Run is the ________ change in a line from one point to another.
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3 years ago
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1. How much work is done on a 20-N rock that you lift 1.5 meters up?
RUDIKE [14]

Answer:

= 30 joules

Step-by-step explanation:

Work done is given by the product of Force and distance

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Force = 20 N , distance = 1.5 m

Thus;

Work done = 20 N × 1.5 m

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3 years ago
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the answer is yes they will use the same amount

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