The answer should be <span>−<span><span>15<span>a^6</span></span><span>b^5</span></span></span>+<span><span>12a</span><span>b^<span>2
Hope I helped</span></span></span>
Easy and simple:::::
4(2x-3)=3+8x-11
Solve for x, i.e separate x in one side and the other terms in the other side
8x - 12 = 8x - 8
8x - 8x = -8 + 12
This equation has all real number as solutions.....infinite number of solutions
The quotient may be greater than or less than the dividend or divisor.
When the dividend is less than the divisor, the quotient will be less than one.
When the dividend is greater than the divisor, the quotient will be greater than one.
Answer: t = 6 s
Step-by-step explanation:
When Rose hit the water, the height of the jump is 0, so: h(t) = 0.
Resolving it, we have:
-16t² + 16t + 480 = 0
To simplify the second degree equation, divided it by 16:
-t² + t + 30 = 0
Now, solve the equation using Bhaskara:
Δ = 1² - 4. (-1) . 30
Δ = 1 + 120
Δ = 121
t = 
t₁ = 
= - 5
t₂ = 
= 6
Since time can be negative, it took t = 6s for Rose to hit the water.
