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Trava [24]
3 years ago
9

What is 10 + 12 and what is 12 + 10

Mathematics
2 answers:
Romashka [77]3 years ago
8 0

22.....................

:):(


Sedbober [7]3 years ago
7 0

Hi ^-^

Answer: for both it's 22


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Ms. Curtis studies 25 hours for 2 tests, and studies 100 hours for how many tests?
enot [183]

Answer:

8

Step-by-step explanation:

Set up a ratio problem:

25 hours/2 tests = 100 hours/x

25x = 200

x = 8

4 0
3 years ago
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Find the 12th term of an AP of the form 7, 12, 17, 22
ikadub [295]
Answer: 62

Step-by-Step Explanation:

First Term (a) = 7
Common Difference (d) = 12 - 7 = 5
Term to Find (n) = 12th

Therefore, finding the 12th Term :-
=> a+(n-1)d
= 7 + (12 - 1)5
= 7 + (11)5
= 7 + 55
=> 62

Hence, 12th Term of this AP is 62
4 0
2 years ago
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Write the equation g(x) in vertex form of a
DerKrebs [107]

The equation g(x) in vertex form of a  quadratic function for the transformations  whose graph is a  translation 4 units left and 1 unit up of the  graph of f(x) is (x-4)² + 1

Given a  quadratic function for the transformations given  the function f(x) = x²

If the function g(x) of the graph is translated 4 units to the left, the equation becomes (x-4)² (note that we subtracted 4 from the x value

  • Translating the graph 1 unit up will give the final function g(x) as (x-4)² + 1 (We added 1 since it is an upward translation.)

Hence the equation g(x) in vertex form of a  quadratic function for the transformations  whose graph is a  translation 4 units left and 1 unit up of the  graph of f(x) is (x-4)² + 1

Learn more here: brainly.com/question/15381183

8 0
2 years ago
What is the vlaue of (2/7)³ ?
vekshin1

Answer:

0

Step-by-step explanation:

5 0
3 years ago
Imagine that you need to compute e^0.4 but you have no calculator or other aid to enable you to compute it exactly, only paper a
labwork [276]

Answer:

0.0032

Step-by-step explanation:

We need to compute e^{0.4} by the help of third-degree Taylor polynomial that is expanded around at x = 0.

Given :

e^{0.4} < e < 3

Therefore, the Taylor's Error Bound formula is given by :

$|\text{Error}| \leq \frac{M}{(N+1)!} |x-a|^{N+1}$   , where $M=|F^{N+1}(x)|$

         $\leq \frac{3}{(3+1)!} |-0.4|^4$

         $\leq \frac{3}{24} \times (0.4)^4$

         $\leq 0.0032$

Therefore, |Error| ≤ 0.0032

4 0
3 years ago
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