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Ivenika [448]
3 years ago
8

5x - 2y = 10 x + 4y = 2

Mathematics
1 answer:
8090 [49]3 years ago
7 0

Answer:

- 40

Step-by-step explanation:

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The sum of the digits of a three digit number is 19. The second digit is one more than the first digit. The third
Oxana [17]

Answer:

  • D. 568

Step-by-step explanation:

Let the number is in the form of xyz

<h3>We have</h3>

Sum of the digits is 19

  • x + y + z = 19

The second digit is one more than the first digit

  • y = x + 1

The third digit is two more than the second digit

  • z = y + 2 = x + 1 + 2 = x + 3

<u>Substitute the values of y and z</u> into the first equation and solve for x

  • x + x + 1 + x + 3 = 19
  • 3x + 4 = 19
  • 3x = 15
  • x = 5

<u>Find the value of y and z</u>

  • y = 5 + 1 = 6
  • z = 5 + 3 = 8

The number is 568

5 0
2 years ago
What is the solution to the equation g(x+2) = 27? (1 point)
Anna11 [10]
X= 2.5
Hope this helps !
8 0
3 years ago
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Cari owns a horse farm and a horse trailer that can transport up to 8,000 pounds of livestock and tack. She travels with 5 horse
Serggg [28]
5 horses with a combined weight of 6,240 pounds
horse trailer has a limit of 8,000 pounds of horse and tacks.

Find the weight of tack, t, for each horse that Cari can allow.

5t + 6,240 <  8,000

5t + 6,240 < 8,000
    - 6,240    -6,240
5t              < 1,760
<span>÷5                 ÷5    </span>
 t               <  352

Each horse can carry a tack that weighs no more than 352 pounds. 

Any tack that weighs beyond <span>352 </span>pounds is will exceed the maximum carrying capacity of the horse trailer.


4 0
2 years ago
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Solve for x.<br>this is for the k12 test.​
Sidana [21]

Answer:

d

Step-by-step explanation:

3 0
2 years ago
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Dy/dx of ln(x/x^²+1)
exis [7]

\dfrac{dy}{dx}\ \ln\left(\dfrac{x}{x^2+1}\right)=\dfrac{1}{\frac{x}{x^2+1}}\cdot\dfrac{x'(x^2+1)-x(x^2+1)'}{(x^2+1)^2}\\\\=\dfrac{x^2+1}{x}\cdot\dfrac{1(x^2+1)-x(2x)}{(x^2+1)^2}=\dfrac{1}{x}\cdot\dfrac{x^2+1-2x^2}{x^2+1}=\dfrac{1-x^2}{x^3+x}\\\\Used:\\\\(\ln(x))'=\dfrac{1}{x}\\\\\left[f(g(x))\right]'=f'(g(x))\cdot g'(x)\\\\\left(\dfrac{f(x)}{g(x)}\right)'=\dfrac{f'(x)g(x)-f(x)g'(x)}{[g(x)]^2}

5 0
3 years ago
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