Answer:
22. Perimeter = 52 units
Area = 160 Square Units
23. Notation form : 
Standard Form : 200000
Step-by-step explanation:
22.
The formula for perimeter is
P = 2 (length + Width )
= 2 ( 2x+3x+1)
= 2(5x+1)
The Formula for Area of a rectangle is
A= length x width
A= 
A=
Now we have to find the Perimeter and Area for x = 5
P = 2(5 x 5 +1)
P= 2(26)
P=52 units
A= 6 x 5 x 5 + 2 x 5
A= 150 + 10
A= 160 square units
23.
A. By using rule of exponents , we can determine that both the results will be same.
B.
Miriam's calculation



Priya's calculation



Standard notation

Answer:

Step-by-step explanation:
1. Shifting
right or left, top or down, as the graph in the question has the same illustration of
. Consider

2. find a and b by using two sample points from the graph:
and 

Area is calculated by taking the length times the width.
A=lxw
one shed is 9 x 4 =36 square feet.
the other shed will be the same but have a four sides equal.
a shed with side of 6 x 6 will have a area of 36 square feet.
one side of the square shed would be 6 feet.
brainliest is always appreciated..

This happens whenever

or

. More generally,

whenever you start with one of these angles and add any multiple of

, so the general solution would be

, where

is any integer. (Notice that when

, you end up with

.)