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Eva8 [605]
3 years ago
9

You and five of your friends ordered your tickets online together. JetBlue ticket prices cost $289 round-trip including tax. The

y also charge you one time fee of $7.99 for the movie channel service that is used on the plane for all passengers in your party ....
Question #1: Write a linear equation that represents the cost of the flight. (slope-intercept form) * *
3 points
Mathematics
1 answer:
baherus [9]3 years ago
5 0

Answer:

y= 288x + 7.99

Step-by-step explanation:

# of tickets : x

y = 289x + 7.99

⬇️ _________ put in y = mx + b

y = 289(6) + 7.99

⬇️ _________ plug in

y = 1734 + 7.99

⬇️ _________ Add

y = 1741.99

HOPE THIS HELPS! (:

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X=2y+11 <br> -7x-27=-13<br> solve with substitution
Lilit [14]

Answer:

x=13/7,    y=-32/7

Step-by-step explanation:

Just trust me

8 0
3 years ago
The advertised size of a computer or television screen is actually the length of the diagonal of
andreyandreev [35.5K]

Answer:

37.5 cm

Step-by-step explanation:

See attached for reference.

let the diagonal be x,

By Pythagorean formula:

x² = (22.5)² + (30)²

x = √[(22.5)² + (30)²]

x = 37.5 cm

4 0
3 years ago
What expressions are equivalent to 3 and 7tenths ​
rewona [7]

Answer:

3 7/10 = 37/10

Step-by-step explanation:

8 0
3 years ago
A certain firm has plants A, B, and C producing respectively 35%, 15%, and 50% of the total output. The probabilities of a non-d
Sliva [168]

Answer:

There is a 44.12% probability that the defective product came from C.

Step-by-step explanation:

This can be formulated as the following problem:

What is the probability of B happening, knowing that A has happened.

It can be calculated by the following formula

P = \frac{P(B).P(A/B)}{P(A)}

Where P(B) is the probability of B happening, P(A/B) is the probability of A happening knowing that B happened and P(A) is the probability of A happening.

-In your problem, we have:

P(A) is the probability of the customer receiving a defective product. For this probability, we have:

P(A) = P_{1} + P_{2} + P_{3}

In which P_{1} is the probability that the defective product was chosen from plant A(we have to consider the probability of plant A being chosen). So:

P_{1} = 0.35*0.25 = 0.0875

P_{2} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{2} = 0.15*0.05 = 0.0075

P_{3} is the probability that the defective product was chosen from plant B(we have to consider the probability of plant B being chosen). So:

P_{3} = 0.50*0.15 = 0.075

So

P(A) = 0.0875 + 0.0075 + 0.075 = 0.17

P(B) is the probability the product chosen being C, that is 50% = 0.5.

P(A/B) is the probability of the product being defective, knowing that the plant chosen was C. So P(A/B) = 0.15.

So, the probability that the defective piece came from C is:

P = \frac{0.5*0.15}{0.17} = 0.4412

There is a 44.12% probability that the defective product came from C.

3 0
4 years ago
Joel Bradley purchased a new cooler for his florist shop for $4,500. He wants to finance it with an installment loan from his ba
Bas_tet [7]

Answer:

62.22% I think.

Step-by-step explanation:

Have a good day.

5 0
2 years ago
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