Solve for x in X-2 (x=8)
Substitute X=8 into 3x - 6y =18 (24-6y=18)
Solve for y in 24-6y=18 (y=1)
X=8 and y=1
Let
be the mean of
. Then
For a random variable
following the standard normal distribution, we have
Transform the random variable to get this critical value in terms of
:
The length of BD is √182
<h3>How to solve for x?</h3>
The given parameters are:
AD = 7
DC = 26
BD = x
The side lengths are represented by the following ratio:
7 : x = x : 26
Express as fraction
7/x = x/26
Cross multiply
x^2 = 182
Take the square roots
x = √182
Hence, the length of BD is √182
Read more about right triangles at:
brainly.com/question/2437195
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0.11 is the answer...not that hard
Hello,
-9n²+79=-18n
==>9n²-18n-79=0
==>9(n²-2n+1-1)-79=0
==>9(n-1)²-88=0
==>[3(n-1)-2√22][3(n-1)+2√22]=0
==>3(n-1)=2√22 or 3(n-1)=-2√22
==>n-1=2/3*√22 or n-1=-2/3*√22
==>n=1+2/3*√22 or n=1-2/3*√22
