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puteri [66]
3 years ago
8

Exercise 5.6.6: Selecting a committee of senators. About A country has two political parties, the Demonstrators and the Repudiat

ors. Suppose that the national senate consists of 100 members, 44 of which are Demonstrators and 56 of which are Rupudiators. (a) How many ways are there to select a committee of 10 senate members with the same number of Demonstrators and Repudiators? Suppose that each party must select a speaker and a vice speaker. How many ways are there for the two speakers and two vice speakers to be selected? Feedback?
Mathematics
1 answer:
krok68 [10]3 years ago
3 0

Answer:

There are 4,148,350,734,528 ways

Step-by-step explanation:

We have

  • 44 senators which are Demonstrators.
  • 56 senators which are Repudiators.

(a) How many ways are there to select a committee of 10 senate members with the same number of Demonstrators and Repudiators?

We want to choose 5 Demonstrators and 5 Repudiators. The number of ways to do this is {44} \choose {5} and 56 \choose 5 respectively. Therefore, the number of ways to select the committee is given by:

{{44}\choose {5}} \times {{56}\choose{5}}=\frac{44!}{39!5!}\times\frac{56!}{51!5!}=\frac{44!56!}{51!39!5!5!}=\frac{44\times43\times42\times41\times40\times56\times55\times54\times53\times52}{5!5!}=\\\\=\frac{44\times43\times42\times41\times8\times56\times11\times54\times53\times52}{4!4!}= \frac{11\times43\times42\times41\times2\times56\times11\times54\times53\times52}{3!3!}=\\\\\frac{11\times43\times14\times41\times2\times56\times11\times18\times53\times52}{2!2!}=

11\times43\times14\times41\times28\times11\times18\times53\times52=4,148,350,734,528

(b) Suppose that each party must select a speaker and a vice speaker. How many ways are there for the two speakers and two vice speakers to be selected?

  • <u>If the speaker and vice speaker are chosen between all senators:</u> In this case, the answer will be

44\times43\times56\times55=5,827,360.

This is because there are (in the case of Demonstrators) 44 possibilities to choose an speaker and after choosing one, there would be 43 possibilities to choose a vice speaker. The same situation happens in the case of Repudiators.

  • <u>If the speaker and vice speaker are chosen between the committee:</u> In this case, the answer will be

5\times4\times5\times4=400.

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hjlf

Answer:

Distance: \sqrt{13} units

Step-by-step explanation:

The distance formula is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where:

  • d is the distance between points (x_1,y_1) and (x_2,y_2)
  • (x_1,y_1) are the coordinates of the first point
  • (x_2,y_2) are the coordinates of the second point

We are given that:

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To determine the value of our distance, d, we plug in our given information into the formula and solve for

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

d=\sqrt{(-6-(-8))^2+(7-10)^2}

d=\sqrt{(-6+8)^2+(-3)^2}

d=\sqrt{(2)^2+(-3)^2}

d=\sqrt{4+9}

d=\sqrt{13}

Therefore, the distance between (-8,10) and (-6,7) is \sqrt{13} units.

See the attached graph for a visual.

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3 years ago
Jon is decorating a panner for a parade. Jon uses a piece of red ribbon witch is 3 4ths yard long. Jon also needs blue ribbon th
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Answer:

John needs 3\frac{3}{4}  yards of blue ribbon.

Step-by-step explanation:

We have been given that Jon uses a piece of red ribbon witch is 3/4th yard long. Jon also needs blue ribbon that is 5 times as long as the ribbon. We are asked to find the amount of blue ribbon that John needs.

To find the amount of blue ribbon that John needs, we will multiply amount of red ribbon by 5 as shown below:

\text{Amount of blue ribbon}=5\times \frac{3}{4}

\text{Amount of blue ribbon}=\frac{5\times 3}{4}

\text{Amount of blue ribbon}=\frac{15}{4}

\text{Amount of blue ribbon}=3\frac{3}{4}

Therefore, John needs 3\frac{3}{4}  yards of blue ribbon.

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