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artcher [175]
2 years ago
6

if a and b are the measures of two first quadrant angles and sin a = 4/5 and sin b = 5/13, find sin a+b.

Mathematics
2 answers:
Blababa [14]2 years ago
8 0
<span> given that sin a= 4/5
cos a= √(1-sin²a)
         = √(1-16/25)
         = √(9/25)
         = 3/5
sin b=5/13
cos b= √(1-sin²b)
         = √(1-25/169)
         = √(144/169)
         = 12/13

sin(a+b)= sin a· cos b + cos a · sin b
              = 4/5· 12/13 + 3/5· 5/13
              = 48/65+15/65
               = 63/65
hope it helps
</span>
SOVA2 [1]2 years ago
6 0

Answer:

[A]  sin(a + b) = \frac{63}{65}

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Answer: x=4

Step-by-step explanation:

1.5(x+4)-3=(x-2)

1.5x+6)-3=4.5x-9

1.5x+3=4.5x-9

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1.5x+12=4.5x

divide 1.5x and 4.5

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11.01

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A storage container for oil is in the shape of a cylinder with a diameter of 10 feet and a height of 17 feet which measurement i
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3 years ago
I beg someone to answer ive posted this 3 times and im still not sure how to do it.....
Anni [7]

Answer:

D) 3 X 10⁷

Step-by-step explanation:

<u>Estimated days:</u>

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3 years ago
9. In a rhombus whose side measures 34 and the smaller angle is 42°. Find the length of the larger diagonal, to the nearest tent
Veseljchak [2.6K]

Answer:

63.5

Step-by-step explanation:

The diagonals of a rhombus bisect opposite angles.

The longer diagonal bisects the 42° angle

The larger angle of the rhombus is 180 - 42 = 138

Let x = the length of the longer diagonal

You know two sides and the included angle of a triangle.

Using the law of cosines we get

x^{2} = 34^{2} + 34^{2} -2(34)(34) cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.150837...\\x = \sqrt{4030.150837} = 63.48x^{2} = 34^{2} + 34^{2} -2(34)(34)cos 138\\         = 1156 + 1156 - 2312 cos 138\\         = 4030.1508...\\     x = \sqrt{4030.1508} \\          =  63.48x^2 = 34^2 + 34^2 - 2(34)(34) cos 138

      = 1156 + 1156 - 2312 c0s 138

      = 4030.1508...

x = sq rt 4030.1508...

  =  63.5

7 0
2 years ago
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