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artcher [175]
3 years ago
6

if a and b are the measures of two first quadrant angles and sin a = 4/5 and sin b = 5/13, find sin a+b.

Mathematics
2 answers:
Blababa [14]3 years ago
8 0
<span> given that sin a= 4/5
cos a= √(1-sin²a)
         = √(1-16/25)
         = √(9/25)
         = 3/5
sin b=5/13
cos b= √(1-sin²b)
         = √(1-25/169)
         = √(144/169)
         = 12/13

sin(a+b)= sin a· cos b + cos a · sin b
              = 4/5· 12/13 + 3/5· 5/13
              = 48/65+15/65
               = 63/65
hope it helps
</span>
SOVA2 [1]3 years ago
6 0

Answer:

[A]  sin(a + b) = \frac{63}{65}

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1. Refer to the equation 3x − 5y = 15. (a) Create a table of values for at least 4 points. Show your work on how you found the v
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Answer:

We have the equation:

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a) We want to create a table with at least 4 points.

To do this, first, let's write the equation as a function: We must isolate one of the variables. Let's isolate y.

5y = 3x - 15

y = (3/5)*x - 3.

Then we have a linear equation.

Now, we can input different values of x, and see what value takes y in each case, then in this way we can be sure that the points will be on the line.

x = 0.

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Then we have the point (0, -3).

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Then we have the point (10, 3).

Now we can create the table

\left[\begin{array}{ccc}x&y\\0&-3\\1&-12/5\\5&0\\10&3\end{array}\right]

Below you can see a graph, where the blue dots are our 4 points, and the green line is the line that represents the equation.

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