Answer:
Let x = the third side
In a triangle, the sum of any 2 sides must be larger than the third side.
I believe this is called the triangle inequality theorem.
We can construct 3 inequalities to obtain the range of values for the third side.
(Inequality #1) 12 + 4 > x
16 > x
(Inequality#2) 12 + x > 4
x > -8 (we can discard this ... we know all sides will be positive)
(Inequality #3) 4 + x > 12
x > 8
So when we combine these together,
8 < x < 16
X (the third side) must be a number between 8 and 16. but not including 8 and 16
Answer:
2 5/8
Step-by-step explanation:
1 3/4 + 7/8
add the fractions together
look for the lcm bwt 4 and 8
1 6 + 7
____
8
= 13/8 = 1 5/8
1 + 1 5/8
= 2 5/8
Answer:
1. w = 15
2. b = 4.8
3. s = 9.7
4. p =15
5. m = -3.2
Step-by-step explanation:
1.w + 10 = 25
we have to find the value of w, so moving 10 from left side to right side
w= 25 - 10
w = 15
2. 7.2 + b = 12
we have to find the value of w, so moving 7.2 from left side to right side
b= 12 - 7.2
b= 4.8
3. 5.3 + s = 15
s= 15 - 5.3
s= 9.7
4.p + (-25) = -10
p-25 = -10
p= -10 + 25
p= 15
3. m + (-1.6) = -4.8
m - 1.6 = -4.8
m = -4.8 + 1.6
m= -3.2
A 45° sector is 1/8 of the area of the circle, so is (72π m^2)/8 = 9π m^2.
