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posledela
3 years ago
5

PLEASEEEEE HELPPPPP SIXTH GRADE MATH HELPPP

Mathematics
1 answer:
Nonamiya [84]3 years ago
6 0
Any given point on a graph follows the format (x,y). In this case, the x-value is 4 and the y-value is 0. We know that the horizontal axis is the x-axis (left and right movement) and the vertical axis is the y-axis (up and down movement). We can use this knowledge to find the point (4,0).

Starting at (0,0), we move 4 spaces to the right (x-value) and 0 spaces up/down (y-value). This leaves us in a position much like that of Point B on the graph above. Therefore, the point closest to (4,0) is Point B.

I hope this helps!
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3 years ago
How do I do question 9 & 11? Please help thank you!
Novay_Z [31]
<h2>9.</h2><h3>Given</h3>
  • sphere with radius 15 cm
<h3>Find</h3>
  • linear approximation to the volume when the radius increases 0.4 cm
<h3>Solution</h3>

The equation for volume of a sphere is

... V = (4/3)π·r³

Differentiating gives

... dV = 4π·r²·dr

Filling in the given numbers gives

... change in volume ≈ 4π·(15 cm)²·(0.4 cm)

... = 360π cm³ ≈ 1130.97 cm³ . . . . . . volume of layer 4mm thick

<h2>11.</h2><h3>Given</h3>
  • an x by x by 2x cuboid with surface area 129.6 cm²
  • rate of change of x is 0.01 cm/s
<h3>Find</h3>
  • rate of change of volume
<h3>Solution</h3>

The area is that of two cubes of dimension x joined together. The area of each such cube is 6x², but the two joined faces don't count in the external surface area. Thus the area of the cuboid is 10x².

The volume of the cuboid is that of two cubes joined, so is 2x³. Then the rate of change of volume is

... dV/dt = (d/dt)(2x³) = 6x²·dx/dt

We know x² = A/10, where A is the area of the cuboid, so the rate of change of volume is ...

... dV/dt = (6/10)A·dx/dt = 0.6·(129.6 cm²)(0.01 cm/s)

... dV/dt = 0.7776 cm³/s

5 0
3 years ago
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