The answer is
x+y=10
20x+30y=280
2x^2y^2 - 7xy + 5y^2 + 8xy - 3y^2 + x^2y^2 + 4y^2
3x^2y^2 - 7xy + 5y^2 + 8xy -3y^2 + 4y^2
3x^2y^2 + xy + 5y^2 - 3y^2 + 4y^2
3x^2y^2 + xy +6y^2
<span>So we want to know what MAD from this set of data is that has the mean value of 4. First we determine the distance d of each number from the set from the mean value: d1=4-3=1, d2=4-4=0, d3=5-4=1, d4=6-4=2. So our set of distances is {1,1,1,1,0,0,0,1,1,2}. Now we can determine MAD: MAD=(1+1+1+1+0+0+0+1+1+2)/10=0.8.</span>
We should first find the gas mileage
that will be 535/21 equals to 25.5
The car's gas mileage is 25.5
To find how much the car can drive on 51 gallons of gas
25.5×51
Equals to 1300.5
the car can drive 1300.5 miles on 51 gallons of gas
