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Nostrana [21]
3 years ago
14

he dot plot below shows 6 data points with a mean of 16. A dot plot going from 11 to 20. 1 dot is above 12, 13, 15, 17, 19, 20.

What is the absolute deviation at 19? 3 4 7 8
Mathematics
1 answer:
puteri [66]3 years ago
7 0

Answer:

The absolute deviation at 19 is 3.

Step-by-step explanation:

The absolute and mean absolute deviation show the amount of deviation (variation) that occurs around the mean score.

Since we are only interested in the deviations of the scores and not whether they are above or below the mean score, we can ignore the minus sign and take only the absolute value, giving us the absolute deviation.

We are asked to find the absolute deviation at 19.

the given mean is 16.

Hence, the deviation is:

19-16= -3.

Hence the absolute deviation at 19 is |-3|=3.

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Please help me, i will give you brainliest
True [87]

Answer:

4

Step-by-step explanation:

(segment piece) x (segment piece) =   (segment piece) x (segment piece)

JN* NK = LN * NM

3x = 2*6

3x = 12

Divide by 3

3x/3 =12/3

x =4

6 0
3 years ago
The ages of two brothers are in the ratio two to three, but in eight years, the ratio of their ages will be three to four. What
Darina [25.2K]
X = older brother
y = younger brother 

Equation 1: x/y = 2/3 ⇒ x = 2y/3
Equation 2: x + 8/y + 8 = 3/4

( \frac{2y}{3} + 8) / y +8 =  \frac{3}{4}
(2y + 24)/3 = y + 8 =  \frac{3}{4}
2y + 24 = 3 (y + 8) =  \frac{3}{4}
2y + 24 = 3y + 24 =  \frac{3}{4}
4 (2y + 24) = 3 (3y + 24)
8y + 96 = 9y + 72
y = 24

The age of the older brother is 24.

x =  \frac{2y}{3} = \frac{2*24}{3}
x =  \frac{48}{3}
x = 16

The age of the youngest brother is 16.
5 0
3 years ago
Read 2 more answers
Find the greatest common multiple of 12 and 8
Mama L [17]
Find the greatest common multiple of 12 and 8 is 4
5 0
3 years ago
Read 2 more answers
3x^2-12+(x-4)(2-x)-(x^2-4x+4)
bogdanovich [222]

Answer:

x² + 10x - 24

Step-by-step explanation:

3x² - 12 + (x - 4)(2 - x) - (x² - 4x + 4)

= 3x² - 12 + (2x - x² - 8 + 4x) - x² + 4x - 4

= 3x² - 12 + 2x - x² - 8 + 4x - x² + 4x - 4

= x² + 10x - 24

4 0
3 years ago
A driver intends to complete 2 laps on a track that is exactly 1 mile around at an average speed of 60 mph. He gets off to a slo
andrey2020 [161]

Answer:

Goal is not achievable

Step-by-step explanation:

There are Two laps and the total distance here is 2miles. Now, it is said that he hopes to travel at a speed of 60mph, thus the total time that it would take him to complete the 2 miles distance race is 2/60 = 1/30 hours. Thus if he travels at a constant speed of 60mph he would finish the race at 1/30hours.

This means he will take a time of 1/60 hours per lap.

Now, he travels 30mph to complete 1 mile, the time taken for this is 1/30h

We now need to know the speed he travels on the second lap.

Average speed = Total distance/Total time

60mph = 2/( 1/30 + T2)

60 = 2/( (1 + 30T2)/30)

60 = 2 divided by (1 + 30T2)/30

60 = 2 * (30)/1 + 30T2

60( 1 + 30T2) = 60

1 + 30T2 = 1

30T2 = 0

T2 = 0

This means that he cannot achieve his goal again as he had taken the time meant for the whole race in a single lap.

4 0
4 years ago
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