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Nostrana [21]
3 years ago
14

he dot plot below shows 6 data points with a mean of 16. A dot plot going from 11 to 20. 1 dot is above 12, 13, 15, 17, 19, 20.

What is the absolute deviation at 19? 3 4 7 8
Mathematics
1 answer:
puteri [66]3 years ago
7 0

Answer:

The absolute deviation at 19 is 3.

Step-by-step explanation:

The absolute and mean absolute deviation show the amount of deviation (variation) that occurs around the mean score.

Since we are only interested in the deviations of the scores and not whether they are above or below the mean score, we can ignore the minus sign and take only the absolute value, giving us the absolute deviation.

We are asked to find the absolute deviation at 19.

the given mean is 16.

Hence, the deviation is:

19-16= -3.

Hence the absolute deviation at 19 is |-3|=3.

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the decimal is .40

Step-by-step explanation:

1/5 = 20%/.20

So if 1/5 is 20% 2/5 should just have 20% more resolving in 40% or .40

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3 years ago
How many points are contained on a line?
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What kind of line? In order to answer this we have to know if its a graph line such as linear or if its a number line.

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If 3m equals 129, then what is m?<br> 3m=129<br> m?
Ksivusya [100]
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4 years ago
A builder buys bricks at the rate of $4.50 per brick for the first 10, $3.50 per brick for the next 10, and $2.50 for any additi
iogann1982 [59]
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8 0
3 years ago
Enunciado:Si una empresa determina que sus costos obedecen a un modelo lineal y además sabe que si produce $10$ unidades sus cos
const2013 [10]

Responder:

y = 200x + 2000

Explicación paso a paso:

Deje que la ecuación lineal se exprese como y = mx + c

m es la pendiente

c es la intersección

Si la empresa produce $ 10 unidades, sus costos totales son $ 4000 dólares y si produce $ 15 unidades sus costos ascienden a $ 5000 dólares, entonces podemos representar esto como puntos de coordenadas;

(10,4000) y (15,5000)

Conseguir la pendiente

m = 5000-4000 / 15-10

m = 1000/5

m = 200

Obtener la intersección c

Sustituya m = 2000 y el punto (10, 4000) en la fórmula y = MX + c

4000 = 200 (10) + c

4000-2000 = c

c = 2000

Sustituya m = 200 y c = 2000 en la ecuación y = mx + c

y = 200x + 2000

Por tanto, la expresión lineal requerida es y = 200x + 2000

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3 years ago
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